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At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.

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\[4x^2-17x-42=0\] Factor the left side:)
It'd be something like: (4x+7)(x-6)?? I don't know if this is right...
expand (4x+7)(x-6) to see if it works...

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Not exactly sure if I'm targeting it right.. but 6?
|dw:1438776516354:dw| it works out
Ok, then I probably stated the question wrong... The actual question is: The length of a rectangle is 17 centimeters less than four times its width. Its area is 42 square centimeters. Find the dimensions of the rectangle. Use the formula area=length*width
ah... that's what happened..
Yeah sorry.
It's ok. I'll figure it out somehow..
translate it into math equation The length of a rectangle is 17 centimeters less than four times its width. Its area is 42 square centimeters. |dw:1438776955499:dw| area = 22 now use that formula L times w =42 so two equations are L=4w-17 L times w =42 substitute L in 2nd equation for its value \[\huge\rm w(\color{reD}{4w-17})=42\] you get 4w^2-14w-42 so when you factor it out you will get (4w-17)(w-6) now set both parentheses equal to 0 and then solve for w w-6=0 w= ?
so factor of 4w^2 -17 -42 is correct s UsukiDoll mentioned foil method to check if it correct or not
its*
Thanks! I've got it figured out!

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