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YanaSidlinskiy

  • one year ago

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  1. YanaSidlinskiy
    • one year ago
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    \[4x^2-17x-42=0\] Factor the left side:)

  2. YanaSidlinskiy
    • one year ago
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    It'd be something like: (4x+7)(x-6)?? I don't know if this is right...

  3. UsukiDoll
    • one year ago
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    expand (4x+7)(x-6) to see if it works...

  4. YanaSidlinskiy
    • one year ago
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    Not exactly sure if I'm targeting it right.. but 6?

  5. UsukiDoll
    • one year ago
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    |dw:1438776516354:dw| it works out

  6. YanaSidlinskiy
    • one year ago
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    Ok, then I probably stated the question wrong... The actual question is: The length of a rectangle is 17 centimeters less than four times its width. Its area is 42 square centimeters. Find the dimensions of the rectangle. Use the formula area=length*width

  7. UsukiDoll
    • one year ago
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    ah... that's what happened..

  8. YanaSidlinskiy
    • one year ago
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    Yeah sorry.

  9. YanaSidlinskiy
    • one year ago
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    It's ok. I'll figure it out somehow..

  10. Nnesha
    • one year ago
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    translate it into math equation The length of a rectangle is 17 centimeters less than four times its width. Its area is 42 square centimeters. |dw:1438776955499:dw| area = 22 now use that formula L times w =42 so two equations are L=4w-17 L times w =42 substitute L in 2nd equation for its value \[\huge\rm w(\color{reD}{4w-17})=42\] you get 4w^2-14w-42 so when you factor it out you will get (4w-17)(w-6) now set both parentheses equal to 0 and then solve for w w-6=0 w= ?

  11. Nnesha
    • one year ago
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    so factor of 4w^2 -17 -42 is correct s UsukiDoll mentioned foil method to check if it correct or not

  12. Nnesha
    • one year ago
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    its*

  13. YanaSidlinskiy
    • one year ago
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    Thanks! I've got it figured out!

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