anonymous
  • anonymous
What is the solution set of y=x2+2x+7 and y=x+7?
Mathematics
  • Stacey Warren - Expert brainly.com
Hey! We 've verified this expert answer for you, click below to unlock the details :)
SOLVED
At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.
jamiebookeater
  • jamiebookeater
I got my questions answered at brainly.com in under 10 minutes. Go to brainly.com now for free help!
anonymous
  • anonymous
@Astrophysics
Astrophysics
  • Astrophysics
What method, substitution, elimination, matrices, etc?
anonymous
  • anonymous
it doesnt tell me
1 Attachment

Looking for something else?

Not the answer you are looking for? Search for more explanations.

More answers

Astrophysics
  • Astrophysics
You can solve for x by setting y = y so you get \[x^2+2x+7=x+7\]
Astrophysics
  • Astrophysics
What do you get when you solve for x here?
anonymous
  • anonymous
2x^3 i think
anonymous
  • anonymous
Go to math way .com. It is also an app. Gives me almost every single math answer I can think of except word problems
Astrophysics
  • Astrophysics
No, you need to factor so you have \[x^2+2x+7=x+7 \implies x^2+2x+7-x-7=0 \implies x^2+x=0\] now solve for x.
Astrophysics
  • Astrophysics
\[x^2+x=0\] you can complete the square if you like
Astrophysics
  • Astrophysics
Though you can just do \[x(x-1)=0\] now what are the roots?
Astrophysics
  • Astrophysics
^ this will give your x values, once you find that just plug it in either of the original equations above to get the corresponding y value, it will be easier if you plug the x values in y = x+7, this will give you your (x,y) solutions where you should have two.
anonymous
  • anonymous
x^2+2x+7=x+7 subtract x+7 on both sides of the equation x^2+x=0 I think the answers are: x = 1 x = 0
Astrophysics
  • Astrophysics
@badsuns can you please stop giving out the answers.
anonymous
  • anonymous
@Astrophysics just trying to help, but i'll stop. sorry about that. i'm not 100% sure on this answer anyway.
Astrophysics
  • Astrophysics
Thanks

Looking for something else?

Not the answer you are looking for? Search for more explanations.