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anonymous
 one year ago
What is the solution set of y=x2+2x+7 and y=x+7?
anonymous
 one year ago
What is the solution set of y=x2+2x+7 and y=x+7?

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Astrophysics
 one year ago
Best ResponseYou've already chosen the best response.0What method, substitution, elimination, matrices, etc?

Astrophysics
 one year ago
Best ResponseYou've already chosen the best response.0You can solve for x by setting y = y so you get \[x^2+2x+7=x+7\]

Astrophysics
 one year ago
Best ResponseYou've already chosen the best response.0What do you get when you solve for x here?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Go to math way .com. It is also an app. Gives me almost every single math answer I can think of except word problems

Astrophysics
 one year ago
Best ResponseYou've already chosen the best response.0No, you need to factor so you have \[x^2+2x+7=x+7 \implies x^2+2x+7x7=0 \implies x^2+x=0\] now solve for x.

Astrophysics
 one year ago
Best ResponseYou've already chosen the best response.0\[x^2+x=0\] you can complete the square if you like

Astrophysics
 one year ago
Best ResponseYou've already chosen the best response.0Though you can just do \[x(x1)=0\] now what are the roots?

Astrophysics
 one year ago
Best ResponseYou've already chosen the best response.0^ this will give your x values, once you find that just plug it in either of the original equations above to get the corresponding y value, it will be easier if you plug the x values in y = x+7, this will give you your (x,y) solutions where you should have two.

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0x^2+2x+7=x+7 subtract x+7 on both sides of the equation x^2+x=0 I think the answers are: x = 1 x = 0

Astrophysics
 one year ago
Best ResponseYou've already chosen the best response.0@badsuns can you please stop giving out the answers.

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0@Astrophysics just trying to help, but i'll stop. sorry about that. i'm not 100% sure on this answer anyway.
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