Max observes the zoo and the library from a helicopter flying at a height of 200 times square root of 3 feet above the ground, as shown below:

At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.

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Max observes the zoo and the library from a helicopter flying at a height of 200 times square root of 3 feet above the ground, as shown below:

Geometry
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At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.

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What is the distance between the zoo and the library?
90/?

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|dw:1438783098376:dw| i think first you need to find hypotenuse side of right triangle by using \[\rm sin \rm \theta = \frac{ opposite }{ hypotenuse }~~~~ \cos \theta = \frac{ adjacent }{ hypotenuse } ~~\tan \theta = \frac{ opposite }{ adjacent }\]
|dw:1438783160804:dw| blue line = hypotenuse
use sin function \[\rm sin 60= \frac{ opposite }{ hypotenuse }\]
oh i got the answer but ill wait for nnesha :)
@Nnesha 400 right?
Hoe did you get that answer?
oh so you saw the answer huh? :/ lol
how* SORRY
that should help
and there are a few more questions that i think you didnt post yet but are yours?
if it helped the medal will be waiting for me :) xD
.
what @nnesha?
what ? let me know if you still don't get anything :=)
  • phi
are you studying trigonometry (using sin and cos) or are you supposed to be using "special triangles" in this case, 30-60-90 triangles?
@phi Im studying trig
  • phi
in that case, use nnesha's picture notice in the red triangle, \[\tan 60 = \frac{200\sqrt{3}}{x} \] tan 60 is one of those values you should memorize. it is sqr(3) thus \[ \sqrt{3}= \frac{200\sqrt{3}}{x} \\ x= 200\] now for the large triangle \[ \tan 30 = \frac{200\sqrt{3}}{x} \] tan 30 = 1/sqrt(3) so you have \[ \frac{1}{\sqrt{3} }= \frac{200\sqrt{3}}{x} \] hopefully you find x= 600 thus the bottom of the big triangle is 600 the distance from G to zoo is 200 the difference is the distance from the zoo and library.

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