## anonymous one year ago Max observes the zoo and the library from a helicopter flying at a height of 200 times square root of 3 feet above the ground, as shown below:

1. anonymous

2. anonymous

What is the distance between the zoo and the library?

3. ali2x2

90/?

4. Nnesha

|dw:1438783098376:dw| i think first you need to find hypotenuse side of right triangle by using $\rm sin \rm \theta = \frac{ opposite }{ hypotenuse }~~~~ \cos \theta = \frac{ adjacent }{ hypotenuse } ~~\tan \theta = \frac{ opposite }{ adjacent }$

5. Nnesha

|dw:1438783160804:dw| blue line = hypotenuse

6. Nnesha

use sin function $\rm sin 60= \frac{ opposite }{ hypotenuse }$

7. ali2x2

oh i got the answer but ill wait for nnesha :)

8. ali2x2

@Nnesha 400 right?

9. anonymous

Hoe did you get that answer?

10. ali2x2

oh so you saw the answer huh? :/ lol

11. anonymous

how* SORRY

12. ali2x2
13. ali2x2

that should help

14. ali2x2

and there are a few more questions that i think you didnt post yet but are yours?

15. ali2x2

if it helped the medal will be waiting for me :) xD

16. Nnesha

.

17. anonymous

what @nnesha?

18. Nnesha

what ? let me know if you still don't get anything :=)

19. phi

are you studying trigonometry (using sin and cos) or are you supposed to be using "special triangles" in this case, 30-60-90 triangles?

20. anonymous

@phi Im studying trig

21. phi

in that case, use nnesha's picture notice in the red triangle, $\tan 60 = \frac{200\sqrt{3}}{x}$ tan 60 is one of those values you should memorize. it is sqr(3) thus $\sqrt{3}= \frac{200\sqrt{3}}{x} \\ x= 200$ now for the large triangle $\tan 30 = \frac{200\sqrt{3}}{x}$ tan 30 = 1/sqrt(3) so you have $\frac{1}{\sqrt{3} }= \frac{200\sqrt{3}}{x}$ hopefully you find x= 600 thus the bottom of the big triangle is 600 the distance from G to zoo is 200 the difference is the distance from the zoo and library.