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anonymous

  • one year ago

Max observes the zoo and the library from a helicopter flying at a height of 200 times square root of 3 feet above the ground, as shown below:

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  1. anonymous
    • one year ago
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  2. anonymous
    • one year ago
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    What is the distance between the zoo and the library?

  3. ali2x2
    • one year ago
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    90/?

  4. Nnesha
    • one year ago
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    |dw:1438783098376:dw| i think first you need to find hypotenuse side of right triangle by using \[\rm sin \rm \theta = \frac{ opposite }{ hypotenuse }~~~~ \cos \theta = \frac{ adjacent }{ hypotenuse } ~~\tan \theta = \frac{ opposite }{ adjacent }\]

  5. Nnesha
    • one year ago
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    |dw:1438783160804:dw| blue line = hypotenuse

  6. Nnesha
    • one year ago
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    use sin function \[\rm sin 60= \frac{ opposite }{ hypotenuse }\]

  7. ali2x2
    • one year ago
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    oh i got the answer but ill wait for nnesha :)

  8. ali2x2
    • one year ago
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    @Nnesha 400 right?

  9. anonymous
    • one year ago
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    Hoe did you get that answer?

  10. ali2x2
    • one year ago
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    oh so you saw the answer huh? :/ lol

  11. anonymous
    • one year ago
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    how* SORRY

  12. ali2x2
    • one year ago
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    http://openstudy.com/study#/updates/53bc4175e4b0bbb79bdb2c9a

  13. ali2x2
    • one year ago
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    that should help

  14. ali2x2
    • one year ago
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    and there are a few more questions that i think you didnt post yet but are yours?

  15. ali2x2
    • one year ago
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    if it helped the medal will be waiting for me :) xD

  16. Nnesha
    • one year ago
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    .

  17. anonymous
    • one year ago
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    what @nnesha?

  18. Nnesha
    • one year ago
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    what ? let me know if you still don't get anything :=)

  19. phi
    • one year ago
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    are you studying trigonometry (using sin and cos) or are you supposed to be using "special triangles" in this case, 30-60-90 triangles?

  20. anonymous
    • one year ago
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    @phi Im studying trig

  21. phi
    • one year ago
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    in that case, use nnesha's picture notice in the red triangle, \[\tan 60 = \frac{200\sqrt{3}}{x} \] tan 60 is one of those values you should memorize. it is sqr(3) thus \[ \sqrt{3}= \frac{200\sqrt{3}}{x} \\ x= 200\] now for the large triangle \[ \tan 30 = \frac{200\sqrt{3}}{x} \] tan 30 = 1/sqrt(3) so you have \[ \frac{1}{\sqrt{3} }= \frac{200\sqrt{3}}{x} \] hopefully you find x= 600 thus the bottom of the big triangle is 600 the distance from G to zoo is 200 the difference is the distance from the zoo and library.

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