## just_one_last_goodbye one year ago Can anyone help me? Medal and Fan

1. just_one_last_goodbye

Hey @satellite73 give me a sec

2. just_one_last_goodbye

$\sqrt{18} + \sqrt{2}$

3. Nnesha

what are factors of 18 ?

4. just_one_last_goodbye

Which statement is true about the expression? It is rational and equal to 3. It is rational and equal to 4. It is irrational and equal to 3 multiplied by the square root of 2. It is irrational and equal to 4 multiplied by the square root of 2.

5. just_one_last_goodbye

Factors of 18 are 6 x 3

6. just_one_last_goodbye

2 x 9

7. Nnesha

^ better one of number must be perfect square root |dw:1438785939285:dw| now take square root of 9

8. just_one_last_goodbye

OK

9. just_one_last_goodbye

What now?

10. Nnesha

square root of 9 = 3 $\huge\rm 3\sqrt{2}+\sqrt{2}$ square root of common in both terms so take it out

11. just_one_last_goodbye

So A correct?

12. just_one_last_goodbye

since it's equal to 3?

13. Nnesha

how is it equal to 3 ?

14. just_one_last_goodbye

9 = 3 x 3

15. Nnesha

when you take out sqrt from 3sqrt{2} what will u have left ?

16. just_one_last_goodbye

OH I see now so it's C?

17. Nnesha

in other words divide both terms by common factor which is square root 2 $\frac{ 3\sqrt{2} }{ \sqrt{2} }+\frac{ \sqrt{2} }{ \sqrt{2} }$\$\sqrt{2}(?????)$ sqr{2} divide by square root 2 = ?

18. just_one_last_goodbye

Is it 2?

19. Nnesha

$\frac{ \sqrt{2} }{ \sqrt{2} }$ i said divide not multiply :=)

20. just_one_last_goodbye

1?

21. Nnesha

yes right so when you take out sqr{2} from sqrt{2} 1 is left |dw:1438786438226:dw| when you take out square root of 2 from 3sqrt{2} 3 is left so now combine 3+1 = answer

22. just_one_last_goodbye

4

23. Nnesha

yes right so 4sqrt{2}

24. just_one_last_goodbye

Thanks so much @Nnesha

25. Nnesha

my pleasure.