Can anyone help me? Medal and Fan

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Hey @satellite73 give me a sec
\[\sqrt{18} + \sqrt{2}\]
what are factors of 18 ?

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Which statement is true about the expression? It is rational and equal to 3. It is rational and equal to 4. It is irrational and equal to 3 multiplied by the square root of 2. It is irrational and equal to 4 multiplied by the square root of 2.
Factors of 18 are 6 x 3
2 x 9
^ better one of number must be perfect square root |dw:1438785939285:dw| now take square root of 9
OK
What now?
square root of 9 = 3 \[\huge\rm 3\sqrt{2}+\sqrt{2}\] square root of common in both terms so take it out
So A correct?
since it's equal to 3?
how is it equal to 3 ?
9 = 3 x 3
when you take out sqrt from 3sqrt{2} what will u have left ?
OH I see now so it's C?
in other words divide both terms by common factor which is square root 2 \[\frac{ 3\sqrt{2} }{ \sqrt{2} }+\frac{ \sqrt{2} }{ \sqrt{2} }\]\\[\sqrt{2}(?????)\] sqr{2} divide by square root 2 = ?
Is it 2?
\[\frac{ \sqrt{2} }{ \sqrt{2} }\] i said divide not multiply :=)
1?
yes right so when you take out sqr{2} from sqrt{2} 1 is left |dw:1438786438226:dw| when you take out square root of 2 from 3sqrt{2} 3 is left so now combine 3+1 = answer
4
yes right so 4sqrt{2}
Thanks so much @Nnesha
my pleasure.

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