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anonymous
 one year ago
find the area of the region bounded by the graphs of f(x) = x^3 + 4x^2  12x and g(x) = x^2 +2x.
Please show the steps. No need to explaib.
anonymous
 one year ago
find the area of the region bounded by the graphs of f(x) = x^3 + 4x^2  12x and g(x) = x^2 +2x. Please show the steps. No need to explaib.

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ali2x2
 one year ago
Best ResponseYou've already chosen the best response.1have you tried tigeralgebra.com?

OregonDuck
 one year ago
Best ResponseYou've already chosen the best response.0@ali2x2 are you going to help him?

ali2x2
 one year ago
Best ResponseYou've already chosen the best response.1@OregonDuck its ok you can help him

OregonDuck
 one year ago
Best ResponseYou've already chosen the best response.0nevermind i was going to suggest tiger too lol

Astrophysics
 one year ago
Best ResponseYou've already chosen the best response.1Your graph is dw:1438787787036:dw so your integral is \[\int\limits_{a}^{b} [g(x)f(x)]dx\] where your interval is a=0, b = 2

Astrophysics
 one year ago
Best ResponseYou've already chosen the best response.1\[\int\limits_{0}^{2} [(x^2+2x)(x^3+4x^212x)] dx\]

Astrophysics
 one year ago
Best ResponseYou've already chosen the best response.1Now go ahead and integrate :)

ali2x2
 one year ago
Best ResponseYou've already chosen the best response.1umg i thought @OregonDuck already did the work, im missing out! ;o

Astrophysics
 one year ago
Best ResponseYou've already chosen the best response.1dw:1438788387136:dw a clearer graph, where f(x) is red and g(x) is blue.

Astrophysics
 one year ago
Best ResponseYou've already chosen the best response.1So the area is dw:1438788598493:dw the idea for the integral is basically this \[\int\limits_{a}^{b} [ \text{Top functionBottom function}] dx\]

Astrophysics
 one year ago
Best ResponseYou've already chosen the best response.1@Yaros Does that make sense?

Astrophysics
 one year ago
Best ResponseYou've already chosen the best response.1Hey, so just to make sure you got it, \[\int\limits\limits\limits_{0}^{2} [(x^2+2x)(x^3+4x^212x)] dx = \int\limits\limits_{0}^{2} (x^35x^2+14x)dx\] \[[\frac{ x^4 }{ 4 }\frac{ 5x^3 }{ 3 }+7x^2] _{0}^2 =\frac{ (2)^4 }{ 4 }\frac{ 5(2)^3 }{ 3 }+7(2)^20 = \frac{ 32 }{ 3 }\]
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