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anonymous

  • one year ago

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  1. anonymous
    • one year ago
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    Which of the following inequalities is modeled by the graph? A)2x + 5y ≥ 14; x ≥ 0 B)2x + 5y ≤ 14; x ≥ 0 C)2x − 5y ≤ 14; x ≥ 0 D)−2x − 5y ≤ 14; x ≥ 0

  2. anonymous
    • one year ago
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    @ganeshie8 @phi @igreen

  3. Haseeb96
    • one year ago
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    well both x and y values are in +ve quadrant so answer must have +ve signs of x and y values now tell me what can be the answer

  4. anonymous
    • one year ago
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    its A? @Haseeb96

  5. mathstudent55
    • one year ago
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    It can't be A, because in A, the shaded part is above the line.

  6. anonymous
    • one year ago
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    so.. idk

  7. mathstudent55
    • one year ago
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    |dw:1438790214899:dw|

  8. mathstudent55
    • one year ago
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    When the equation of the line is written in y = mx + b form, then the shading is below the line when the equal sign is replaced with < or <=.

  9. mathstudent55
    • one year ago
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    You have shading below the line, so your equation must be of the form \(y \le mx + b\) It can't be \(y \ge mx + b\)

  10. mathstudent55
    • one year ago
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    A)2x + 5y ≥ 14 ----> y ≥ -2/5 x + 14/5 B)2x + 5y ≤ 14 ----> y ≤ -2/5x + 14/5 C)2x − 5y ≤ 14 ----> y ≥ 2/5 x - 14/5 D)−2x − 5y ≤ 14 ----> y ≥ -2/5 x - 14/5

  11. anonymous
    • one year ago
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    wait im thinking

  12. mathstudent55
    • one year ago
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    The inequality has to have a negative slope (A, B, D), a positive y-intercept (A, B), and a \(\le\) sign (B, C, D). Which is the only letter in common in those characteristics?

  13. anonymous
    • one year ago
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    B? @mathstudent55

  14. mathstudent55
    • one year ago
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    Yes.

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