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anonymous

  • one year ago

PLEASE HELP!!!!! MEDAL AND FAN!!!!! 26. Give the center coordinates (x,y) of the circle: (x + 3)2 + (y - 4)2 = 36 27. Give the radius of the circle: (x + 3)2 + (y - 4)2 = 36 28. Give the center coordinates (x,y) of the circle: (x + 1)2 + (y - 6)2 = 2.25 29. Give the radius of the circle: (x + 1)2 + (y - 6)2 = 2.25

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  1. anonymous
    • one year ago
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    @satellite73

  2. anonymous
    • one year ago
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    this is 26? \[(x+3)^2+(y-4)^2=36\]

  3. anonymous
    • one year ago
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    But how do I solve it?

  4. anonymous
    • one year ago
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    center of the circle has got to do with the 3 and the 4

  5. anonymous
    • one year ago
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    when the center shift left it becomes (x+h)^2 and (x-h)^2 when it shifts right, same with the y axis

  6. anonymous
    • one year ago
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    wait would the answer to number 26 be -3,4

  7. anonymous
    • one year ago
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    yes

  8. anonymous
    • one year ago
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    now for the radius you know the circle comes in this package \[(x+3)^2+(y-4)^2=36\]which is equivalent to \[(x+h)^2+(y-k)^2=r^2\]

  9. anonymous
    • one year ago
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    Would it be 6?

  10. anonymous
    • one year ago
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    yes

  11. anonymous
    • one year ago
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    now use the same method for 28 & 29

  12. anonymous
    • one year ago
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    So 28 is -6,1

  13. anonymous
    • one year ago
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    And 29 is 1.5

  14. anonymous
    • one year ago
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    Is tha correct?

  15. anonymous
    • one year ago
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    *that

  16. anonymous
    • one year ago
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    no and yes

  17. anonymous
    • one year ago
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    you swapped the x and y position for 28

  18. anonymous
    • one year ago
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    So it's 1,-6

  19. anonymous
    • one year ago
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    yes

  20. anonymous
    • one year ago
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    -1,6

  21. anonymous
    • one year ago
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    Oh okay thanks for you help.

  22. anonymous
    • one year ago
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    not -6,1

  23. anonymous
    • one year ago
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    yw

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