anonymous
  • anonymous
PLEASE HELP!!!!! MEDAL AND FAN!!!!! 26. Give the center coordinates (x,y) of the circle: (x + 3)2 + (y - 4)2 = 36 27. Give the radius of the circle: (x + 3)2 + (y - 4)2 = 36 28. Give the center coordinates (x,y) of the circle: (x + 1)2 + (y - 6)2 = 2.25 29. Give the radius of the circle: (x + 1)2 + (y - 6)2 = 2.25
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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jamiebookeater
  • jamiebookeater
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anonymous
  • anonymous
@satellite73
anonymous
  • anonymous
this is 26? \[(x+3)^2+(y-4)^2=36\]
anonymous
  • anonymous
But how do I solve it?

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anonymous
  • anonymous
center of the circle has got to do with the 3 and the 4
anonymous
  • anonymous
when the center shift left it becomes (x+h)^2 and (x-h)^2 when it shifts right, same with the y axis
anonymous
  • anonymous
wait would the answer to number 26 be -3,4
anonymous
  • anonymous
yes
anonymous
  • anonymous
now for the radius you know the circle comes in this package \[(x+3)^2+(y-4)^2=36\]which is equivalent to \[(x+h)^2+(y-k)^2=r^2\]
anonymous
  • anonymous
Would it be 6?
anonymous
  • anonymous
yes
anonymous
  • anonymous
now use the same method for 28 & 29
anonymous
  • anonymous
So 28 is -6,1
anonymous
  • anonymous
And 29 is 1.5
anonymous
  • anonymous
Is tha correct?
anonymous
  • anonymous
*that
anonymous
  • anonymous
no and yes
anonymous
  • anonymous
you swapped the x and y position for 28
anonymous
  • anonymous
So it's 1,-6
anonymous
  • anonymous
yes
anonymous
  • anonymous
-1,6
anonymous
  • anonymous
Oh okay thanks for you help.
anonymous
  • anonymous
not -6,1
anonymous
  • anonymous
yw

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