anonymous
  • anonymous
Given f(x)=3x^2+18x+6 where is its vertex?
Mathematics
jamiebookeater
  • jamiebookeater
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Nnesha
  • Nnesha
formula to find x coordinate of vertex \[\huge\rm x=\frac{ -b }{ 2a }\] and then substitute x in f(x) function for x value to find y
Nnesha
  • Nnesha
a and b are \[\huge\rm Ax^2+Bx+C=0\] a=leading coefficient b=middle term
anonymous
  • anonymous
so just solve it first

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Nnesha
  • Nnesha
yes right first find x-coordinate
anonymous
  • anonymous
21x?
Nnesha
  • Nnesha
how did you get that ?
Nnesha
  • Nnesha
a= ?? b= ?
anonymous
  • anonymous
a=3x^2 b=18x
Nnesha
  • Nnesha
just the coefficient
Nnesha
  • Nnesha
so a=3 b=18 now use that formula that i posted bove
anonymous
  • anonymous
-3
Nnesha
  • Nnesha
nvm yes
Nnesha
  • Nnesha
now to find y coordinate of vertex substitute all x in f(x) function for -3
anonymous
  • anonymous
so its -3, -21
Nnesha
  • Nnesha
yes right

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