PLEASE HELP!!!
A 19.4 gram sample of gas is found to have a volume of 1.3 liters at 282 K and 1.2 atm. What is the molar mass of this gas? Show all of the work used to solve this problem.

- anonymous

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- arindameducationusc

Use PV=nRT

- arindameducationusc

here T=282
V=1.82
P=1.2
R=0.0821
and n=m/M we need M, so put m=19.4 to get M

- arindameducationusc

It should look1.2*1.82=(19.4/M)*0.0821*282

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## More answers

- arindameducationusc

@fenispart Got it?

- anonymous

@arindameducationusc Yeah I understand now. I got 289.55

- anonymous

@arindameducationusc I also need help with one last one:
A solution is made by dissolving 23.5 grams of glucose (C6H12O6) in .245 kilograms of water. If the molal freezing point constant for water (Kf) is -1.86 °C/m, what is the resulting Δtf of the solution? Show all the steps taken to solve this problem.

- arindameducationusc

Didn't I give you the formula last time?
Okay I will show again...

- arindameducationusc

\[\Delta{T}=K _{f}* W _{b}*1000/ Mw _{b}*W _{a}\]
Here Mwb= 180 because C6H12O6
6*12+12*1+6*1=180

- arindameducationusc

convert .245 kg to gram....

- anonymous

25.4g

- arindameducationusc

you get 245 gram
(This is Wa)

- arindameducationusc

1kg=1000grams

- arindameducationusc

and Wb is 19.4, and the rest is given in question...
Got it?

- arindameducationusc

@fenispart Can you solve now?

- anonymous

Is 19.4 always Wb?

- arindameducationusc

No not always, but for this question 19.4 is Wb

- anonymous

How do you find Wb?

- arindameducationusc

hmmmm....Its given in the question.... READ THE QUESTION

- anonymous

Wait are we talking about the first question or the second one?

- arindameducationusc

oops... my bad...... its second question and Wb is 23.5.

- arindameducationusc

sorry about that

- arindameducationusc

23.5 is given... I guess now you got it. Both questions are about gas so.... I made a mistake........

- arindameducationusc

Can you do now? @fenispart

- anonymous

How do I find Kf? @arindameducationusc

- arindameducationusc

Kf is given -1.86

- anonymous

I got -0.991 @arindameducationusc

- arindameducationusc

Total answer?

- anonymous

Yes

- anonymous

@arindameducationusc

- arindameducationusc

i m here

- arindameducationusc

Yes your answer is correct....

- arindameducationusc

I just checked it... Good job! Bravo!

- anonymous

Thank you so much!

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