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anonymous

  • one year ago

please help im so stuck Given the following functions f(x) and g(x), solve f over g (−5) and select the correct answer below: f(x) = 2x − 20 g(x) = x − 1

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  1. DanJS
    • one year ago
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    f(-5) / g(-5) that right?

  2. anonymous
    • one year ago
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    -5 is one of the choices but im not sure

  3. anonymous
    • one year ago
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    could you explain to me how you got that answer?

  4. anonymous
    • one year ago
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    −5 5 one sixth 30 the coices

  5. DanJS
    • one year ago
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    \[\frac{ f(-5) }{ g(-5) } = \frac{ 2(-5)-20 }{ -5 -1 }\]

  6. DanJS
    • one year ago
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    right , yeah it is f(-5) / g(-5), just evaluate both and put them over each other

  7. anonymous
    • one year ago
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    ok thank you can you help with few more just trying out openstudy for the first time my friends said it helps

  8. DanJS
    • one year ago
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    yes, depends on who helps ya.. .. just ask a new thread

  9. anonymous
    • one year ago
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    you mean like post the question by itself?

  10. DanJS
    • one year ago
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    screw it, here is fine

  11. anonymous
    • one year ago
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    ok 1 sec

  12. anonymous
    • one year ago
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    given the functions f(x)and g(x), solve (f times g)(3) and select the correct answer below f(x)4x^2+12 g(x)=x-1

  13. DanJS
    • one year ago
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    f times g, or is it a small circle looking thing

  14. anonymous
    • one year ago
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    47 -47 96 -96 are choices

  15. anonymous
    • one year ago
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    its a small cirlce

  16. DanJS
    • one year ago
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    ok, then it is a compound function f[g(x)]

  17. anonymous
    • one year ago
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    so how would i set up the equation

  18. DanJS
    • one year ago
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    nope, it is gonna be multiplication

  19. DanJS
    • one year ago
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    f(3) * g(3) =

  20. anonymous
    • one year ago
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    so i would multiply the 2 equation they gave me?

  21. anonymous
    • one year ago
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    so (4x^2+12)3 and (x-1)3?

  22. DanJS
    • one year ago
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    you could do that first, or put in the value for x to start, [4(3^2) + 12] * (3-1)

  23. anonymous
    • one year ago
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    hows did you get the value of x

  24. DanJS
    • one year ago
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    THe problem says [f times g ](3) , x=3

  25. DanJS
    • one year ago
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    so you just evaluate both f and g at x=3 , then multiply the values together

  26. anonymous
    • one year ago
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    ooo ok

  27. anonymous
    • one year ago
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    let me try it

  28. DanJS
    • one year ago
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    I have time for one more if you want

  29. DanJS
    • one year ago
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    f(3) * g(3) = [4(3^2) + 12] * (3-1) = 96

  30. anonymous
    • one year ago
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    how did u get 96 i got 168

  31. DanJS
    • one year ago
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    [4*9 + 12]* 2

  32. DanJS
    • one year ago
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    48*2

  33. anonymous
    • one year ago
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    ok and wat a bout the part when you multiply it by 3-1

  34. DanJS
    • one year ago
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    that is what happened, the 2 at the end... f(3) * g(3) = [4(3^2) + 12] * (3-1) = 96

  35. anonymous
    • one year ago
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    ook

  36. anonymous
    • one year ago
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    i get it now i messed up omewhere but i see thay why its a 2 at the end cuz 3-1 is 2 ok can u hepl with one more?

  37. DanJS
    • one year ago
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    yep

  38. anonymous
    • one year ago
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    Given the following functions f(x) and g(x), solve f[g(6)] and select the correct answer below: f(x) = 6x + 12 g(x) = x − 8

  39. anonymous
    • one year ago
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    choices are −96 0 24 48

  40. DanJS
    • one year ago
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    These compound functions like that, you work from the inside most function first, then outwards carrying the values...

  41. DanJS
    • one year ago
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    figure out g(6), then use that value in f(x) for x

  42. anonymous
    • one year ago
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    so x is 6?

  43. DanJS
    • one year ago
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    yes, anytime you see g(#) or f(#) some number, that is what x is

  44. anonymous
    • one year ago
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    k so now i plug it in dont tell me ill tell u n u tell if its right

  45. DanJS
    • one year ago
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    So what is g(6)

  46. anonymous
    • one year ago
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    is it -2?

  47. DanJS
    • one year ago
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    no... First , what is g(6) ?

  48. anonymous
    • one year ago
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    i did x-8 and plugged 6 for x

  49. DanJS
    • one year ago
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    right, so g(6) = 6 - 8 = -2

  50. anonymous
    • one year ago
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    ok so now f

  51. DanJS
    • one year ago
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    now you use that value you just got in the f function for x

  52. anonymous
    • one year ago
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    f is 48?

  53. DanJS
    • one year ago
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    f(-2)

  54. anonymous
    • one year ago
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    6times 6 plus 12

  55. DanJS
    • one year ago
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    no, that is the thing with the compound functions, you have to use the value from g(6) = -2 for the value of x in f(x)

  56. DanJS
    • one year ago
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    Figure the inner function out, use that value in the next function

  57. anonymous
    • one year ago
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    o ok so i plug the -2 in instead of the 6?

  58. DanJS
    • one year ago
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    Yes.. f[g(6)] = f(-2)

  59. anonymous
    • one year ago
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    can you explain how you get that from f(x)=6x+12?

  60. DanJS
    • one year ago
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    ok, start over from the beginning...

  61. anonymous
    • one year ago
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    ok

  62. DanJS
    • one year ago
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    f [ g(6) ] What that means is instead of having the usual f(x), you have f( another function) Start with the inner function g(6) and evaluate. g(6) = -2 Now you can replace g(6) with -2 in the original problem

  63. DanJS
    • one year ago
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    Left to evaluate f(-2)

  64. anonymous
    • one year ago
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    oo ok

  65. anonymous
    • one year ago
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    so where do i go from here?

  66. DanJS
    • one year ago
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    just left to evaluate f(-2) = 6*(-2) + 12

  67. anonymous
    • one year ago
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    o ok so now u added the 6(-2)+12 wouldnt it be 0

  68. DanJS
    • one year ago
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    so it is zero i have to take off, you can fan me , ill prolly be on later

  69. anonymous
    • one year ago
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    ok how do i fan you?

  70. anonymous
    • one year ago
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    nvm n did it thanks

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