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anonymous

  • one year ago

A company estimates its total profit (profit = total revenue minus total cost) as P(x) = 2x^5 − 3x^4 − 5x^2 − 2, where P is in thousands of dollars and x is the number of years elapsed since the company was founded. How many times can the total profit become exactly zero? Hint: Use Descartes's rule of signs.

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  1. anonymous
    • one year ago
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    @Nnesha

  2. anonymous
    • one year ago
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    @pooja195

  3. anonymous
    • one year ago
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    Do you know the Descrates rule of signs

  4. anonymous
    • one year ago
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    no not really

  5. anonymous
    • one year ago
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    The rule states that if the terms of a single-variable polynomial with real coefficients are ordered by descending variable exponent, then the number of positive roots of the polynomial is either equal to the number of sign differences between consecutive nonzero coefficients, or is less than it by an even number. Multiple roots of the same value are counted separately.

  6. anonymous
    • one year ago
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    How many sign changes are there in this polynomial P(x) = 2x^5 − 3x^4 − 5x^2 − 2

  7. anonymous
    • one year ago
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    4

  8. anonymous
    • one year ago
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    there is one sign change

  9. anonymous
    • one year ago
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    P(x) = +2x^5 − 3x^4 − 5x^2 − 2 I see one sign change.

  10. anonymous
    • one year ago
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    You there?

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