solving radical equation please check my answer?

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solving radical equation please check my answer?

Algebra
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At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.

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why wouldn't it be x = 5, not extraneous ?
show your work.plz
i know, I should've subtracted five, and then square booth sides

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Other answers:

wrong.
I had just gone straight to squaring the whole equation?
5 is under the square root so you can't move it to the right without removing square root
then subtract?
lemme resolve
do you still want a picture of my work?
yep
this is how i got the x = 5, not extraneous
1 Attachment
re solving atm
but i did square first there ^
well well well. first step is to divide both side by 2
then take square root both sides
cause of the two infront of the radical?
yep right you need to transfer all numbers that is outside the radical sign to the right side that's always going to be First step
to take square root you need just radical sign at left side
|dw:1438802258254:dw|
2/2 = ?
|dw:1438802316942:dw|
it's not 0
one,
yes right \[\huge\rm \sqrt{x-5}=1\] now solve for x
ohhhhh!
x - 5 = 1 x = 6 not extraneous
true
yay! thank you !
my pleasure :=)

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