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anonymous
 one year ago
solving radical equation please check my answer?
anonymous
 one year ago
solving radical equation please check my answer?

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anonymous
 one year ago
Best ResponseYou've already chosen the best response.0why wouldn't it be x = 5, not extraneous ?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0i know, I should've subtracted five, and then square booth sides

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0I had just gone straight to squaring the whole equation?

Nnesha
 one year ago
Best ResponseYou've already chosen the best response.15 is under the square root so you can't move it to the right without removing square root

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0do you still want a picture of my work?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0this is how i got the x = 5, not extraneous

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0but i did square first there ^

Nnesha
 one year ago
Best ResponseYou've already chosen the best response.1well well well. first step is to divide both side by 2

Nnesha
 one year ago
Best ResponseYou've already chosen the best response.1then take square root both sides

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0cause of the two infront of the radical?

Nnesha
 one year ago
Best ResponseYou've already chosen the best response.1yep right you need to transfer all numbers that is outside the radical sign to the right side that's always going to be First step

Nnesha
 one year ago
Best ResponseYou've already chosen the best response.1to take square root you need just radical sign at left side

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0dw:1438802258254:dw

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0dw:1438802316942:dw

Nnesha
 one year ago
Best ResponseYou've already chosen the best response.1yes right \[\huge\rm \sqrt{x5}=1\] now solve for x

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0x  5 = 1 x = 6 not extraneous
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