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anonymous

  • one year ago

Find the vertex of the graph of the function. f(x) = (x - 5)2 + 10

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  1. anonymous
    • one year ago
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    \[f(x)=(x-5)^{2}+10\]

  2. madhu.mukherjee.946
    • one year ago
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    f(x) = a(x-h)^2 + k --->vertex = (h,k) so vertex is (5,10)

  3. anonymous
    • one year ago
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    (5,10)

  4. anonymous
    • one year ago
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    thank youuuuu

  5. anonymous
    • one year ago
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    what about this one? its a little different Find the vertex of the graph of the function. \[f(x) = 3x ^{2} - 18x + 24\]

  6. anonymous
    • one year ago
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    @madhu.mukherjee.946

  7. madhu.mukherjee.946
    • one year ago
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    f(x)=3x^2-18x+24 completing the square f(x)=3(x^2-6x+9)+24-27 f(x)=3(x-3)^2-3

  8. madhu.mukherjee.946
    • one year ago
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    This is a parabola of the standard form: A(x-h)^2+k, with (h,k) being the (x,y) coordinates of the vertex. Positive leading coefficient means parabola open upwards, has a minimum. For given parabola: vertex: (3,-3)

  9. anonymous
    • one year ago
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    do u need help still?

  10. anonymous
    • one year ago
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    thank you so much!! @madhu.mukherjee.946

  11. madhu.mukherjee.946
    • one year ago
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    your welcome darling:))

  12. anonymous
    • one year ago
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    no i think i got it but thank you @Skielerlucas04 ill tell you if i dont get something else

  13. anonymous
    • one year ago
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    ok

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