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anonymous
 one year ago
Find the vertex of the graph of the function.
f(x) = (x  5)2 + 10
anonymous
 one year ago
Find the vertex of the graph of the function. f(x) = (x  5)2 + 10

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anonymous
 one year ago
Best ResponseYou've already chosen the best response.0\[f(x)=(x5)^{2}+10\]

madhu.mukherjee.946
 one year ago
Best ResponseYou've already chosen the best response.1f(x) = a(xh)^2 + k >vertex = (h,k) so vertex is (5,10)

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0what about this one? its a little different Find the vertex of the graph of the function. \[f(x) = 3x ^{2}  18x + 24\]

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0@madhu.mukherjee.946

madhu.mukherjee.946
 one year ago
Best ResponseYou've already chosen the best response.1f(x)=3x^218x+24 completing the square f(x)=3(x^26x+9)+2427 f(x)=3(x3)^23

madhu.mukherjee.946
 one year ago
Best ResponseYou've already chosen the best response.1This is a parabola of the standard form: A(xh)^2+k, with (h,k) being the (x,y) coordinates of the vertex. Positive leading coefficient means parabola open upwards, has a minimum. For given parabola: vertex: (3,3)

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0do u need help still?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0thank you so much!! @madhu.mukherjee.946

madhu.mukherjee.946
 one year ago
Best ResponseYou've already chosen the best response.1your welcome darling:))

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0no i think i got it but thank you @Skielerlucas04 ill tell you if i dont get something else
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