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itsmichelle29
 one year ago
Help i medal and fan thanks!!!!!!!!
A basketball player gets 2 freethrow shots when she is fouled by a player on the opposing team. She misses the first shot 40% of the time. When she misses the first shot, she misses the second shot 5% of the time. What is the probability of missing both freethrow shots?
itsmichelle29
 one year ago
Help i medal and fan thanks!!!!!!!! A basketball player gets 2 freethrow shots when she is fouled by a player on the opposing team. She misses the first shot 40% of the time. When she misses the first shot, she misses the second shot 5% of the time. What is the probability of missing both freethrow shots?

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anonymous
 one year ago
Best ResponseYou've already chosen the best response.040%=0.40 5%=0.05 You just multiply them together

itsmichelle29
 one year ago
Best ResponseYou've already chosen the best response.0what the formula for that

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0It is used when 2 or more independent events are occurring. The formula would be percentage of probability 1 x percentage of probability 2 or percentage of probability 1 x percentage of probability 2 x percentage of probability 3 if there are 3 independent event and you want to find the probability of it

itsmichelle29
 one year ago
Best ResponseYou've already chosen the best response.0so is it 2% or 45%

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0You were right its 2%. 45% is too off. Think about it.

itsmichelle29
 one year ago
Best ResponseYou've already chosen the best response.0IDK i think its 45

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0No, you multiply 0.05 x 0.40 as I stated earlier which equals to 2. Why would she have a 45% chance to miss BOTH free throws when she has a 5% chance to miss it after missing her first one? Reading the question 5 more time to fully understand the question.

itsmichelle29
 one year ago
Best ResponseYou've already chosen the best response.0Okay thanks im going with what you say thanks ... im wrong

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Yeah, no problem. Feel free to tell me the results.
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