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itsmichelle29

  • one year ago

Help i medal and fan thanks!!!!!!!! A basketball player gets 2 free-throw shots when she is fouled by a player on the opposing team. She misses the first shot 40% of the time. When she misses the first shot, she misses the second shot 5% of the time. What is the probability of missing both free-throw shots?

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  1. anonymous
    • one year ago
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    40%=0.40 5%=0.05 You just multiply them together

  2. itsmichelle29
    • one year ago
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    so 2%

  3. itsmichelle29
    • one year ago
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    what the formula for that

  4. anonymous
    • one year ago
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    It is used when 2 or more independent events are occurring. The formula would be percentage of probability 1 x percentage of probability 2 or percentage of probability 1 x percentage of probability 2 x percentage of probability 3 if there are 3 independent event and you want to find the probability of it

  5. itsmichelle29
    • one year ago
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    so is it 2% or 45%

  6. anonymous
    • one year ago
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    You were right its 2%. 45% is too off. Think about it.

  7. itsmichelle29
    • one year ago
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    IDK i think its 45

  8. itsmichelle29
    • one year ago
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    P(A U B)

  9. anonymous
    • one year ago
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    No, you multiply 0.05 x 0.40 as I stated earlier which equals to 2. Why would she have a 45% chance to miss BOTH free throws when she has a 5% chance to miss it after missing her first one? Reading the question 5 more time to fully understand the question.

  10. itsmichelle29
    • one year ago
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    Okay thanks im going with what you say thanks ... im wrong

  11. anonymous
    • one year ago
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    Yeah, no problem. Feel free to tell me the results.

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