itsmichelle29
  • itsmichelle29
Help i medal and fan thanks!!!!!!!! A basketball player gets 2 free-throw shots when she is fouled by a player on the opposing team. She misses the first shot 40% of the time. When she misses the first shot, she misses the second shot 5% of the time. What is the probability of missing both free-throw shots?
Mathematics
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SOLVED
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schrodinger
  • schrodinger
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anonymous
  • anonymous
40%=0.40 5%=0.05 You just multiply them together
itsmichelle29
  • itsmichelle29
so 2%
itsmichelle29
  • itsmichelle29
what the formula for that

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More answers

anonymous
  • anonymous
It is used when 2 or more independent events are occurring. The formula would be percentage of probability 1 x percentage of probability 2 or percentage of probability 1 x percentage of probability 2 x percentage of probability 3 if there are 3 independent event and you want to find the probability of it
itsmichelle29
  • itsmichelle29
so is it 2% or 45%
anonymous
  • anonymous
You were right its 2%. 45% is too off. Think about it.
itsmichelle29
  • itsmichelle29
IDK i think its 45
itsmichelle29
  • itsmichelle29
P(A U B)
anonymous
  • anonymous
No, you multiply 0.05 x 0.40 as I stated earlier which equals to 2. Why would she have a 45% chance to miss BOTH free throws when she has a 5% chance to miss it after missing her first one? Reading the question 5 more time to fully understand the question.
itsmichelle29
  • itsmichelle29
Okay thanks im going with what you say thanks ... im wrong
anonymous
  • anonymous
Yeah, no problem. Feel free to tell me the results.

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