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anonymous
 one year ago
If sin(theta)=X, then express sec(theta) in terms of x
anonymous
 one year ago
If sin(theta)=X, then express sec(theta) in terms of x

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anonymous
 one year ago
Best ResponseYou've already chosen the best response.0The answer I got was \[\sqrt{1(1/x)^2}\] Would this be correct?

freckles
 one year ago
Best ResponseYou've already chosen the best response.1dw:1438813890812:dw use pythagorean theorem to find the other side

freckles
 one year ago
Best ResponseYou've already chosen the best response.1and recall for secant use hyp/adj

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0I'm sorry, I'm a bit confused where to go from there

freckles
 one year ago
Best ResponseYou've already chosen the best response.1can you find the adjacent side by use of Pythagorean theorem ?

freckles
 one year ago
Best ResponseYou've already chosen the best response.1\[(\text{ adjacent })^2+x^2=1^2 \\ \text{ solve for adjacent }\]

freckles
 one year ago
Best ResponseYou've already chosen the best response.1let me know if you don't know how maybe I can give you a step

freckles
 one year ago
Best ResponseYou've already chosen the best response.1\[( \text{ adjacent } )^2+x^2=1 \\ \text{ subtract} x^2 \text{ on both sides } \\ ( \text{ adjacent })^2=1x^2 \\ \text{ take square root of both sides } \\ \text{ adjacent } = \pm \sqrt{1x^2}\] you cannot simplify this ... if that is what you tried to do

freckles
 one year ago
Best ResponseYou've already chosen the best response.1dw:1438814521770:dw now find sec(theta) using the right triangle

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0The whole negative thing kinda threw me off. Thanks

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0What I tried to do initially was rewrite the identity sin^2+Cos^2=1 and go from there

freckles
 one year ago
Best ResponseYou've already chosen the best response.1\[\sin^2(\theta)+\cos^2(\theta)=1 \\ \text{ we are given } \sin(\theta)=x \text{ so } \sin^2(\theta)=x^2 \\ x^2+\cos^2(\theta)=1 \\ \\ \text{ subtract} x^2 \text{ on both sides } \\ \cos^2(\theta)=1x^2 \\ \text{ take square root of both sides } \\ \cos(\theta)=\pm \sqrt{1x^2}\] then just flip both sides to find sec(theta)

freckles
 one year ago
Best ResponseYou've already chosen the best response.1its the same thing really

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Ooh, I tried to use the recirpocals first, hence why I had (1/x)^2 Thanks a bunch mate (:

freckles
 one year ago
Best ResponseYou've already chosen the best response.1well csc^2(x) would actually be (1/x)^2

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Yeah, I figured if the identity works with sin and cos, it'd work with their reciprocals. I see the error

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Do you think you might be able to help me with one more question?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Evaluate cos1+cos2+cos3+...+cos357+cos358+cos359 (all measurements are in degrees) The only thing I can imagine is that it repeats at a certain point or something

freckles
 one year ago
Best ResponseYou've already chosen the best response.1\[\cos(x)+\cos(180x) \\=\cos(x)+\cos(180)\cos(x)\sin(180)\sin(x) \\ =\cos(x)1\cos(x)0\sin(x)\\ =0\] So I think maybe we can use cos(x)+cos(180x)

freckles
 one year ago
Best ResponseYou've already chosen the best response.1So I think maybe we can use cos(x)+cos(180x)=0*

freckles
 one year ago
Best ResponseYou've already chosen the best response.1\[\cos(1)+\cos(179)=0 \\ \cos(2)+\cos(178)=0 \\ \cos(3)+\cos(177)=0 \\ \cos(4)+\cos(176) =0 \\ \cdots \\ \] and I have to come back to finish this i'm being called away unfortunately

freckles
 one year ago
Best ResponseYou've already chosen the best response.1notice above I put a minus but it doesn't matter that one part is still 0 \[\cos(x)+\cos(180x) \\=\cos(x)+\cos(180)\cos(x)+\sin(180)\sin(x) \\ =\cos(x)1\cos(x)+0\sin(x)\\ =0\] hmm... \[\cos(180)=1 \\ \text{ hmmm... we need to think now for the rest of the finite series }\] like we already know cos(1)+cos(2)+...+cos(180)=1 we need to figure out would to do with cos(181)+cos(182)+cos(183)+...+cos(359) we should be able to think of something similar

freckles
 one year ago
Best ResponseYou've already chosen the best response.1how about for that other sign try to see if something like cos(180+x)+cos(360x)=0 works.. cos(180)cos(x)sin(180)sin(x)+cos(360)cos(x)+sin(360)sin(x) =cos(x)+cos(x)=0
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