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The answer I got was \[\sqrt{1-(1/x)^2}\] Would this be correct?

|dw:1438813890812:dw|
use pythagorean theorem to find the other side

and recall for secant use hyp/adj

I'm sorry, I'm a bit confused where to go from there

can you find the adjacent side by use of Pythagorean theorem ?

\[(\text{ adjacent })^2+x^2=1^2 \\ \text{ solve for adjacent }\]

let me know if you don't know how maybe I can give you a step

adjacent= -x+1?

|dw:1438814521770:dw|
now find sec(theta) using the right triangle

The whole negative thing kinda threw me off. Thanks

What I tried to do initially was rewrite the identity sin^2+Cos^2=1 and go from there

you can use that too

its the same thing really

Ooh, I tried to use the recirpocals first, hence why I had (1/x)^2 Thanks a bunch mate (:

np

well csc^2(x) would actually be (1/x)^2

Do you think you might be able to help me with one more question?

i can try

So I think maybe we can use cos(x)+cos(180-x)=0*

Alright