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there is no graphs
if you think of it as y= 2x and then add 1 y= 2x+1 that is the equation of a line. find two points, plot them , and draw a line through the two points.
Alright. I think I understand. So, if I were to type this into desmos.com what would I do?
type in f(x) + 1 then press add slider i think
ok let me try
It didn't work.
press the play button
kk. Thanks:) Can I ask another question?
Given the parent function f(x) = 2^x, which graph shows f(x) + 1? Going back to the 1st question, the f(x)=2^x is a logarithmic ! So now how do I graph it??
y= 2^x is exponential when x is 0 you have y= 2^0 = 1 (any base to the zero power is 1) x=1, y= 2 x= 2, y= 4 x=3, y=8 plot those points, and put a smooth curve through them if you want y= 2^x + 1 , and 1 to each of the y values: (1,3) (2,5) (3,9) etc. |dw:1438809101764:dw| the curve looks roughly like
ok! so what would be some points it touched?
(-5,1) and (3,5) or (0,2) (-5,1)
some are posted up above. but follow the formula y=2^x + 1 means: multiply 2 by itself x times (or just use a calculator) then add 1
how did you get (-5,1) ?
Whoops! I have no idea
do you have a calculator? what do you get for 2^-5 ?
wouuld (0,2) be a point?
then add 1 (-5, 1.0315) for x=0, y= 2^0 + 1 = 1+1= 2 so (0,2) x=1, 2^1 + 1 = 2 + 1 = 3 so (1,3) you should be able to find a few more.
Oh! Okay thanks so much:)
I need help w/ 1 more. I am going to post it in the open question section:)