anonymous
  • anonymous
What statement correctly describes the key features of the graph of f(x) = 4(1/2)^x + 1 − 3?
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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chestercat
  • chestercat
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anonymous
  • anonymous
@phi
anonymous
  • anonymous
Y-intercept of (0, −1), starts up on the left, gets closer to y = −3 on the right Y-intercept of (0, −1), starts down on the left, gets closer to y = −3 on the right Y-intercept of (0, 1), starts up on the left, gets closer to y = −3 on the right Y-intercept of (0, 1), starts down on the left, gets closer to y = −3 on the right
phi
  • phi
is this \[ y = \left(\frac{1}{2}\right)^{x+1} -3 \]?

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More answers

anonymous
  • anonymous
you forgot the 4 in front of the 1/2
anonymous
  • anonymous
other than that, you were right
phi
  • phi
\[ y = 4\left(\frac{1}{2}\right)^{x+1} -3 \]
anonymous
  • anonymous
yes! :)
phi
  • phi
the y-intercept is the y value when x is 0 any idea what y is when x=0?
anonymous
  • anonymous
1?
phi
  • phi
you erase the x and put 0 in its place in the formula what do you get ?
anonymous
  • anonymous
ok hold on:)
anonymous
  • anonymous
0+1=1 right?
anonymous
  • anonymous
-1! sorry
phi
  • phi
the exponent x+1 becomes 0+1 or just 1 now do (1/2)^ 1 which is just 1/2 then do 1/2 * 4 - 3 or 2 - 3 or -1
phi
  • phi
follow?
anonymous
  • anonymous
yes okay so now we can elimate some answer choices and yes i do
phi
  • phi
yes, it's A or B
phi
  • phi
what do you get for x= -2 any idea?
anonymous
  • anonymous
hold on:)
anonymous
  • anonymous
-5?
phi
  • phi
x+1 becomes -2 + 1 = -1 now do (1/2)^(-1) the negative exponent means you can "flip" the fraction and make the exponent positive so you get 2^1 or just 2 now do 4*2-3 = 8-3 = 5
anonymous
  • anonymous
Oh! I get it :)
phi
  • phi
at x=2, y=5 at x=0, y= -1 starts high on the left and gets smaller (asymptotes to -3)
phi
  • phi
**x=-2 , y=5
anonymous
  • anonymous
I see, I see
anonymous
  • anonymous
so would it be B?
phi
  • phi
yes, I think B. The language is not very clear. (whoever wrote it flunked basic English)
anonymous
  • anonymous
hahah! I totally agree<3 :D

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