could anybody explain thee last step of this proof? where they say Aj1* = Aj1

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could anybody explain thee last step of this proof? where they say Aj1* = Aj1

Mathematics
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At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.

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what's the definition of cofactor?
Aij= (-1)i+j det Aij)

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Other answers:

  • phi
given a matrix, the co-factor of a specific row if found by "crossing off" that row (and the column, for each column) if we are crossing off the jth row of both matrix A and A*, and the only difference between the matrices is the jth row, it should be clear we get the same co-factor for both matrices (when expanding along the jth row)
thanks!

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