The point-slope form of the equation of the line that passes through (–4, –3) and (12, 1) is y – 1 = (x – 12). What is the standard form of the equation for this line?
x – 4y = 8
x – 4y = 2
4x – y = 8
4x – y = 2
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the slope of the line through \((-4,-3)\) and \((12,1)\) is
so the point slope form is not
\[y-1=(x-12)\] it is
first answer is however, correct
can u help me with two more
\[x-4y=8\] is correct
The point-slope form of the equation of the line that passes through (–5, –1) and (10, –7) is y + 7 = (x – 10). What is the standard form of the equation for this line?
2x – 5y = –15
2x – 5y = –17
2x + 5y = –15
2x + 5y = –17
wow still wrong
but you do have a correct answer there
you need method or answer?
go with C
Line CD passes through points C(1, 3) and D(4, –3). If the equation of the line is written in slope-intercept form, y = mx + b, what is the value of b?
aye i got 1 more under it
point slope gives
\[y-3=-2(x-1)\]solve for \(y\) via
y=-2x+5\] so \(b=5\)