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anonymous

  • one year ago

The point-slope form of the equation of the line that passes through (–4, –3) and (12, 1) is y – 1 = (x – 12). What is the standard form of the equation for this line? x – 4y = 8 x – 4y = 2 4x – y = 8 4x – y = 2

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  1. anonymous
    • one year ago
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    wow another set of wrong answers?

  2. anonymous
    • one year ago
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    Standard form is ax + by = c

  3. anonymous
    • one year ago
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    they gave it to me this way how are they wrong

  4. anonymous
    • one year ago
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    the slope of the line through \((-4,-3)\) and \((12,1)\) is \[\frac{1-(-3)}{12-(-4)}=\frac{4}{16}=\frac{1}{4}\]

  5. anonymous
    • one year ago
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    so the point slope form is not \[y-1=(x-12)\] it is \[y-1=\frac{1}{4}(x-12)\]

  6. anonymous
    • one year ago
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    first answer is however, correct

  7. anonymous
    • one year ago
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    can u help me with two more

  8. anonymous
    • one year ago
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    \[x-4y=8\] is correct

  9. anonymous
    • one year ago
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    sure

  10. anonymous
    • one year ago
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    The point-slope form of the equation of the line that passes through (–5, –1) and (10, –7) is y + 7 = (x – 10). What is the standard form of the equation for this line? 2x – 5y = –15 2x – 5y = –17 2x + 5y = –15 2x + 5y = –17

  11. anonymous
    • one year ago
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    wow still wrong but you do have a correct answer there

  12. anonymous
    • one year ago
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    you need method or answer?

  13. anonymous
    • one year ago
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    answer

  14. anonymous
    • one year ago
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    go with C

  15. anonymous
    • one year ago
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    Line CD passes through points C(1, 3) and D(4, –3). If the equation of the line is written in slope-intercept form, y = mx + b, what is the value of b? –5 –2 1 5

  16. anonymous
    • one year ago
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    slope is \[\frac{-3-3}{4-1}=\frac{-6}{3}=-2\]

  17. anonymous
    • one year ago
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    aye i got 1 more under it

  18. anonymous
    • one year ago
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    point slope gives \[y-3=-2(x-1)\]solve for \(y\) via \[y-3=-2x+2\\ y=-2x+5\] so \(b=5\)

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