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AngelaB97
 one year ago
please help me simplify this
x/yy/x
_________
1/x^21/y^2
AngelaB97
 one year ago
please help me simplify this x/yy/x _________ 1/x^21/y^2

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anonymous
 one year ago
Best ResponseYou've already chosen the best response.0\[\frac{ \frac{ x }{ y }\frac{ y }{ x } }{ \frac{ 1 }{ x^2 } \frac{ 1 }{ y^2 }}\]First separate the equations so it can look more simpler.\[(\frac{ x }{ y }\frac{ y }{ x })\div (\frac{ 1 }{ x^2 }\frac{ 1 }{ y^2 })\]

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0When you flip the second equation, the division sign will change to a multiplication sign.\[(\frac{ x }{ y }\frac{ y }{ x })\times(x^2y^2)\]

AngelaB97
 one year ago
Best ResponseYou've already chosen the best response.0yes and then what happens to the denominator?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Look at the first equation now and try to get the denominator's the same by cross multiplying.\[(\frac{ x(x) }{ y(x) }\frac{ y(y) }{ x(y) })\]

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0\[(\frac{ x^2 }{ xy }\frac{ y^2 }{ xy })=(\frac{ x^2y^2 }{ xy })\]

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Now the equation looks like this:\[(\frac{ x^2y^2 }{ xy })\times(x^2y^2)\]

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0The original denominator is made up of 2 different fractions. So they don't have a single reciprocal. Solve these problems by multiplying by 1in the form of the least common denominator divided by itself. The least common denominator of x, y, x², and y² is x²y². dw:1438814492460:dw

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0when you distribute the fractions will clear out

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0\[\frac{ (x^2y^2)(x^2y^2) }{ xy }\]

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0dw:1438814584619:dw

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0\[\frac{ (x^42x^2y^2+y^4) }{ xy }\]

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0dw:1438814672337:dw

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0dw:1438814727794:dw

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0\[\frac{ \frac{ x }{ y }\frac{ y }{ x } }{ \frac{ 1 }{ x^2 }\frac{ 1 }{ y^2 } }\] \[=\frac{ \frac{ x^2y^2 }{ xy } }{ \frac{ y^2x^2 }{ x^2y^2 } }\] \[=\frac{ x^2y^2 }{ xy }\times \frac{ x^2y^2 }{ \left( x^2y^2 \right) }\] =xy
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