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take a 2 out first.
2*(3x^2 - 2x - 1)

okay i did that, then i did 2(3x-3x)(x-1)

you have factors
3 1 --- 1 1
you need to make a -2 out of that , so +3 and -1

explain i dont get it

Here you can put in the x terms since 3 and 1 are the only choice
2*(3x )*(x )

2*(3x 1 )*(x 1)

put in the + or - , so that when you distribute that, you get a -2 on the X term

i already put the x terms in as 2(3x-3x)(x-1)

what do i do next

2*(3x^2 - 2x - 1)
= 2( 3x^2 - 3x + x - 1)
now factor the expression in the parentheses by grouping

first factor 3x^2 - 3x
- take 3x out

so add 3 to both sides?

|dw:1438815014897:dw|

no we are not solving an equation
3x^2 - 3x = 3x(x - 1)
do you get that?

3x is the highest common factor of 3x^2 and 3x

oh so its not 2(3x^2-3x) + (x-1)

well thats on the way to solving it
but we need to factor the first 2 terms first - the 3x^2 - 3x

- thats whats called factoring by grouping - grouping the first 2 terms and the last 2

wait so what happened to the 3x^2

its was split into 3x and x
3x(x - 1)

- that called factroing

oh so its still 3x^2. so why did you multiply x-1 on both sides

oh wait you didnt

because (x - 1) is common to both parts :-
3x( x - 1) + 1(x - 1)

how?

do you see the pattern there?

so b is -2

??

no that was an example of factoring b is just b i could have put any letter i liked there

* from an expression

oh okay so the final result is 2(3x+1)-(x-1)

oh okay i got how you got 2(3x+1)-(x-1)

no there's no - there
the 3 parts multiply each other
its
2(2x +1(x - 1)

gtg
its getting late in the UK

okay thank u

yw

I hate MOndays too!!