Algebra 2 help? I'll loose my life if I do't get this done http://prntscr.com/81bhcy

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Algebra 2 help? I'll loose my life if I do't get this done http://prntscr.com/81bhcy

Mathematics
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answer briefly please
|dw:1438817092059:dw|
I don't mean to be a fanboy, but holy shiz, I can't believe I'm meeting Jim like this

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Other answers:

The bases are the same (both x), so we subtract the exponents |dw:1438817143395:dw|
Okay
|dw:1438817164689:dw|
now simplify (4/3) - (5/6)
LCD?
yes you'll need to find that first, what is the LCD in this case?
3
no
what is the lowest common multiple of 3 and 6?
1?
idk
multiples of 3: 3, 6, 9, 12, ... multiples of 6: 6, 12, 18, ...
nvm its 6
yes
the LCD is 6, so you have to transform each fraction to make sure they all have denominators equal to 6
I'm no good with these, can you give me a walkthrough?
|dw:1438817391007:dw|
what can we multiply top and bottom by to get 6 in the denominator?
2?
yes |dw:1438817451986:dw|
so 4/3 is the same as 8/6
mk
\[\Large {\color{red}{\frac{4}{3}}} - \frac{5}{6} = {\color{red}{\frac{8}{6}}} - \frac{5}{6} =??\]
3/6
which reduces to what
1/2
so we can say this |dw:1438817675532:dw|
mk so am I done with that one?
yes, now simplify the other expression
|dw:1438817769472:dw|
|dw:1438817801342:dw|
All i remember is that you add the exponents, at least those 2 inside
yes, so what is \(\Large x*x^3*x^4\) equal to?
x^7 or 8
recall that \(\Large x = x^1\)
I'd go with 8
\[\Large x*x^3*x^4 = x^1*x^3*x^4 = ?\]
x^8
yes
mk, now for tht 16 on the outside
|dw:1438817927856:dw|
now use this rule \[\LARGE \sqrt[n]{x^m} = x^{m/n}\]
so x^8/16
then 8/16 reduces to ?
1/2
|dw:1438818127887:dw|
Okay, so both were x ^1/2 lol
correct
were they equivalent at start or no
they are completely equivalent as long as x is not 0 if x = 0, then you have a division by zero error in the first expression
Okay, so basically equivalent
yes
Thanks man.
no problem
Got time for one more? Be honest, Idm if you don't
go ahead

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