anonymous
  • anonymous
Algebra 2 help? I'll loose my life if I do't get this done http://prntscr.com/81bhcy
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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chestercat
  • chestercat
I got my questions answered at brainly.com in under 10 minutes. Go to brainly.com now for free help!
anonymous
  • anonymous
answer briefly please
jim_thompson5910
  • jim_thompson5910
|dw:1438817092059:dw|
anonymous
  • anonymous
I don't mean to be a fanboy, but holy shiz, I can't believe I'm meeting Jim like this

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More answers

jim_thompson5910
  • jim_thompson5910
The bases are the same (both x), so we subtract the exponents |dw:1438817143395:dw|
anonymous
  • anonymous
Okay
jim_thompson5910
  • jim_thompson5910
|dw:1438817164689:dw|
jim_thompson5910
  • jim_thompson5910
now simplify (4/3) - (5/6)
anonymous
  • anonymous
LCD?
jim_thompson5910
  • jim_thompson5910
yes you'll need to find that first, what is the LCD in this case?
anonymous
  • anonymous
3
jim_thompson5910
  • jim_thompson5910
no
jim_thompson5910
  • jim_thompson5910
what is the lowest common multiple of 3 and 6?
anonymous
  • anonymous
1?
anonymous
  • anonymous
idk
jim_thompson5910
  • jim_thompson5910
multiples of 3: 3, 6, 9, 12, ... multiples of 6: 6, 12, 18, ...
anonymous
  • anonymous
nvm its 6
jim_thompson5910
  • jim_thompson5910
yes
jim_thompson5910
  • jim_thompson5910
the LCD is 6, so you have to transform each fraction to make sure they all have denominators equal to 6
anonymous
  • anonymous
I'm no good with these, can you give me a walkthrough?
jim_thompson5910
  • jim_thompson5910
|dw:1438817391007:dw|
jim_thompson5910
  • jim_thompson5910
what can we multiply top and bottom by to get 6 in the denominator?
anonymous
  • anonymous
2?
jim_thompson5910
  • jim_thompson5910
yes |dw:1438817451986:dw|
jim_thompson5910
  • jim_thompson5910
so 4/3 is the same as 8/6
anonymous
  • anonymous
mk
jim_thompson5910
  • jim_thompson5910
\[\Large {\color{red}{\frac{4}{3}}} - \frac{5}{6} = {\color{red}{\frac{8}{6}}} - \frac{5}{6} =??\]
anonymous
  • anonymous
3/6
jim_thompson5910
  • jim_thompson5910
which reduces to what
anonymous
  • anonymous
1/2
jim_thompson5910
  • jim_thompson5910
so we can say this |dw:1438817675532:dw|
anonymous
  • anonymous
mk so am I done with that one?
jim_thompson5910
  • jim_thompson5910
yes, now simplify the other expression
jim_thompson5910
  • jim_thompson5910
|dw:1438817769472:dw|
jim_thompson5910
  • jim_thompson5910
|dw:1438817801342:dw|
anonymous
  • anonymous
All i remember is that you add the exponents, at least those 2 inside
jim_thompson5910
  • jim_thompson5910
yes, so what is \(\Large x*x^3*x^4\) equal to?
anonymous
  • anonymous
x^7 or 8
jim_thompson5910
  • jim_thompson5910
recall that \(\Large x = x^1\)
anonymous
  • anonymous
I'd go with 8
jim_thompson5910
  • jim_thompson5910
\[\Large x*x^3*x^4 = x^1*x^3*x^4 = ?\]
anonymous
  • anonymous
x^8
jim_thompson5910
  • jim_thompson5910
yes
anonymous
  • anonymous
mk, now for tht 16 on the outside
jim_thompson5910
  • jim_thompson5910
|dw:1438817927856:dw|
jim_thompson5910
  • jim_thompson5910
now use this rule \[\LARGE \sqrt[n]{x^m} = x^{m/n}\]
anonymous
  • anonymous
so x^8/16
jim_thompson5910
  • jim_thompson5910
then 8/16 reduces to ?
anonymous
  • anonymous
1/2
jim_thompson5910
  • jim_thompson5910
|dw:1438818127887:dw|
anonymous
  • anonymous
Okay, so both were x ^1/2 lol
jim_thompson5910
  • jim_thompson5910
correct
anonymous
  • anonymous
were they equivalent at start or no
jim_thompson5910
  • jim_thompson5910
they are completely equivalent as long as x is not 0 if x = 0, then you have a division by zero error in the first expression
anonymous
  • anonymous
Okay, so basically equivalent
jim_thompson5910
  • jim_thompson5910
yes
anonymous
  • anonymous
Thanks man.
jim_thompson5910
  • jim_thompson5910
no problem
anonymous
  • anonymous
Got time for one more? Be honest, Idm if you don't
jim_thompson5910
  • jim_thompson5910
go ahead

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