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abdullah1995

  • one year ago

A block weighing 300 N slides downwards on the angled surface shown at an initial velocity of 2.5 m/s. At t = 0, a force P with the given orientation is applied until the block stops. Knowing that it took 5 seconds for the block to stop and that the coefficient of kinetic friction μk = 0.1, determine the magnitude of P (picture included in the post)

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  1. abdullah1995
    • one year ago
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    |dw:1438816472330:dw|

  2. IrishBoy123
    • one year ago
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    if you do not get a satisfactory answer here, put this on the physics board and i will help you with it tomorrow.

  3. abdullah1995
    • one year ago
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    Tomorrow would be too late :((( I have solved it but i am not sure if i am getting the right answer :/

  4. abdullah1995
    • one year ago
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    First i broke the forces into components. Added the Fn and Friction force on the diagram and labelled 300N force acting downwards. Once i broke the forces into components i got two equations, one for forces acting on the y-axis and the second for forces acting on the x-axis. -0.4226P + Fn - 281.90 = 0 ---------- Equation (1) 0.9063P - F(f) +102.606 = 0 ---------- Equation (2) Note that F(f) is force of friction. Then i knew that F(f) = Fn x 0.1 from the question so i replaced it F(f) with it. -0.4226P + Fn - 281.90 = 0 0.9063P - 0.1Fn +102.606 = 0 After this i solved these two equations simultaneously and found the value of P. My question/confusion is regarding all the other information given in the question, such as the initial velocity, time etc. I feel like i have done something wrong here. Any guidance would be highly appreciated.

  5. abdullah1995
    • one year ago
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    Force BE: 0.33BE(i) + 0.667BE(j) -0.66BE(k) Force P = 5 Kn (j) |dw:1438840328702:dw|

  6. abdullah1995
    • one year ago
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    |dw:1438841526549:dw|

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