abdullah1995
  • abdullah1995
A block weighing 300 N slides downwards on the angled surface shown at an initial velocity of 2.5 m/s. At t = 0, a force P with the given orientation is applied until the block stops. Knowing that it took 5 seconds for the block to stop and that the coefficient of kinetic friction μk = 0.1, determine the magnitude of P (picture included in the post)
Physics
  • Stacey Warren - Expert brainly.com
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SOLVED
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schrodinger
  • schrodinger
I got my questions answered at brainly.com in under 10 minutes. Go to brainly.com now for free help!
abdullah1995
  • abdullah1995
|dw:1438818371044:dw|
abdullah1995
  • abdullah1995
First i broke the forces into components. Added the Fn and Friction force on the diagram and labelled 300N force acting downwards. Once i broke the forces into components i got two equations, one for forces acting on the y-axis and the second for forces acting on the x-axis. -0.4226P + Fn - 281.90 = 0 ---------- Equation (1) 0.9063P - F(f) +102.606 = 0 ---------- Equation (2) Note that F(f) is force of friction. Then i knew that F(f) = Fn x 0.1 from the question so i replaced it F(f) with it. -0.4226P + Fn - 281.90 = 0 0.9063P - 0.1Fn +102.606 = 0 After this i solved these two equations simultaneously and found the value of P. My question/confusion is regarding all the other information given in the question, such as the initial velocity, time etc. I feel like i have done something wrong here. Any guidance would be highly appreciated.
johnweldon1993
  • johnweldon1993
Hint* If the sum of the forces in the 'x' direction = 0...the block would never have moved. this is a dynamic problem not statics your 'x' equation should be equal to "ma"

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johnweldon1993
  • johnweldon1993
You have the times and velocities in order to solve for 'a' and use it to find your 'P'
abdullah1995
  • abdullah1995
Ah ok i got it Thanks a lot ! Can you please help me with one more problem?
abdullah1995
  • abdullah1995
@johnweldon1993
johnweldon1993
  • johnweldon1993
If I can of course!
abdullah1995
  • abdullah1995
1 Attachment
abdullah1995
  • abdullah1995
I think i have done part A, but i am completely stuck on part B :/
johnweldon1993
  • johnweldon1993
First, can you post what you got from part A
abdullah1995
  • abdullah1995
BE: -4i + 8j -8k ---> BE = 12m |dw:1438834319191:dw|
abdullah1995
  • abdullah1995
L(i) + 6(j) -8(k) ---> CD = \[\sqrt{L^2 +100}\] L|dw:1438834536640:dw|
abdullah1995
  • abdullah1995
this is what i have.
abdullah1995
  • abdullah1995
@johnweldon1993
abdullah1995
  • abdullah1995
@johnweldon1993 don't leave me alone lol, i need help. Please help me :(
abdullah1995
  • abdullah1995
@johnweldon1993 are you still here?

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