## mtimko one year ago A block of copper (c = 390 J/kg°C) is heated from 20.0 C to 60.0 C. How much heat (in J) is absorbed by the copper if its mass is 45.0 g?

1. anonymous

$Q=mc(T_f-T_i)$ Q = (0.045 kg)(390 J/kg°C)(60.0° C - 20°C)

2. arindameducationusc

I agree with @peachpi

3. whpalmer4

just a slight quibble: $Q = (0.045\text{ kg})(390\frac{\text{ J}}{\text{kg }^\circ\text{C}})(60.0\ ^\circ\text{C} - 20.0\ ^\circ \text{C)}$ Don't want to lose those significant figures or mangle the units!