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Janu16

  • one year ago

Given the equation Square root of 8x plus 1 = 5, solve for x and identify if it is an extraneous solution.

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  1. Janu16
    • one year ago
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    |dw:1438822086628:dw| so i checked my answer and i got 2 but thats not one of my answer choice

  2. Janu16
    • one year ago
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    @DanJS

  3. DanJS
    • one year ago
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    hi

  4. DanJS
    • one year ago
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    if that 1 is under the root , you cant just subtract it

  5. DanJS
    • one year ago
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    square both sides first 8x + 1 = 25

  6. Janu16
    • one year ago
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    how did you get 25

  7. DanJS
    • one year ago
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    squared both sides first, removes the root, and 5^2 = 25

  8. Janu16
    • one year ago
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    oh so you solve the whole thing

  9. DanJS
    • one year ago
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    you subtracted a 1 out from underneath the root sign, that is illegal

  10. Janu16
    • one year ago
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    ohok lol

  11. Janu16
    • one year ago
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    so you get 3

  12. DanJS
    • one year ago
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    \[[\sqrt{8x+1}]^2=5^2\]

  13. DanJS
    • one year ago
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    yeah 3

  14. Janu16
    • one year ago
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    thx

  15. DanJS
    • one year ago
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    np

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