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YumYum247
 one year ago
someone please help me?!?!?!?!?
YumYum247
 one year ago
someone please help me?!?!?!?!?

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YumYum247
 one year ago
Best ResponseYou've already chosen the best response.0How do i figure out the distance and displacement???? :(

YumYum247
 one year ago
Best ResponseYou've already chosen the best response.0but before that please check if my drawing is ok???? :)

dan815
 one year ago
Best ResponseYou've already chosen the best response.1wow u went all out with ur measuring lol

YumYum247
 one year ago
Best ResponseYou've already chosen the best response.0dan you are prally that missing brother i always wanted.... :")

YumYum247
 one year ago
Best ResponseYou've already chosen the best response.0when your marks are dangling by a single branch.....you have to XD

arindameducationusc
 one year ago
Best ResponseYou've already chosen the best response.0Displacement= Final positioninitial position

arindameducationusc
 one year ago
Best ResponseYou've already chosen the best response.0for distance, just add 14+6+12+2

YumYum247
 one year ago
Best ResponseYou've already chosen the best response.0but dear there are directions that are opposite to each other and even more weird.... E, N, NE, NE

arindameducationusc
 one year ago
Best ResponseYou've already chosen the best response.0Distance doesnot depend on direction! Only magnitude

YumYum247
 one year ago
Best ResponseYou've already chosen the best response.0how do i subtract out the two vector direction from a one dimentional???

arindameducationusc
 one year ago
Best ResponseYou've already chosen the best response.0Ya, displacement is little complicated here.... give me some time....

arindameducationusc
 one year ago
Best ResponseYou've already chosen the best response.0For distance, just add (simple)

YumYum247
 one year ago
Best ResponseYou've already chosen the best response.0sorry i was referring to displacement......!!!

YumYum247
 one year ago
Best ResponseYou've already chosen the best response.0so what's up with displacement???? ?XD

YumYum247
 one year ago
Best ResponseYou've already chosen the best response.0can someone please check my drawing if i've make it right so we can proceed with the question????

arindameducationusc
 one year ago
Best ResponseYou've already chosen the best response.0Trignometric functions cannot be used here... So, If you have taken accurate scale drawings, The method is absolutely correct.

YumYum247
 one year ago
Best ResponseYou've already chosen the best response.0that's right trig can't be used here since it's not a right triangle....

arindameducationusc
 one year ago
Best ResponseYou've already chosen the best response.0This is a pure scaling and drawing problem... Yup you are right..... Yes because no 90 degrees

YumYum247
 one year ago
Best ResponseYou've already chosen the best response.0the thing is that there are three triangles in this problem...XD

arindameducationusc
 one year ago
Best ResponseYou've already chosen the best response.0If protector is allowed in this question, taking angles and taking length of the distance gives answer.... which you have done....

YumYum247
 one year ago
Best ResponseYou've already chosen the best response.0displacement is my main concern here.....

arindameducationusc
 one year ago
Best ResponseYou've already chosen the best response.0Ofcourse. See the idea is after taking all those angles and carefully going the path, take the final point and the initial point(in this case 0) and take the difference. Got it?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0the question was answered why did you tag me?

YumYum247
 one year ago
Best ResponseYou've already chosen the best response.0@joeyboy111 how do i find the displacement????

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0take the final point and the initial point(in this case 0) and take the difference

johnweldon1993
 one year ago
Best ResponseYou've already chosen the best response.1Displacement, Hmm, I know above we said trig cannot be used...but I cannot see why not? The trip looks like dw:1438831247053:dw If we think about "How far total East did he travel?" and "How far total North did he travel" Then we just have 1 giant right triangle with 2 sides known East...14 + 12sin(15) + 2sin(65) = ? North...6 + 12cos(15) + 2cos(65) = ? It's late so let me know if this is totally wrong

johnweldon1993
 one year ago
Best ResponseYou've already chosen the best response.1Also yes I know my 15 degree angle and 65 degree angled vectors should be swapped...but the equations remain the same 15 should be much more "north" and the 65 should be much more "east"

YumYum247
 one year ago
Best ResponseYou've already chosen the best response.0now worries about the angles, just tell me once i have the followings figured out, then i make a triangle and solve for the hypothenuse ? East...14 + 12sin(15) + 2sin(65) = ? North...6 + 12cos(15) + 2cos(65) = ?

YumYum247
 one year ago
Best ResponseYou've already chosen the best response.0i meant right triagle****

arindameducationusc
 one year ago
Best ResponseYou've already chosen the best response.0@johnweldon1993 for 12km, the angle should be 75

arindameducationusc
 one year ago
Best ResponseYou've already chosen the best response.0and for 2km, angle should be 25

arindameducationusc
 one year ago
Best ResponseYou've already chosen the best response.0Yes trig can be used.. that was cool... @johnweldon1993

johnweldon1993
 one year ago
Best ResponseYou've already chosen the best response.1Well the angles I'm using North 15 degrees east...I'm interpreting as it would be north...but instead its just 15 degrees east of north Thus the reason I'm labeling dw:1438832198665:dw

johnweldon1993
 one year ago
Best ResponseYou've already chosen the best response.1So for that reasoning, is why I'm using "sin" as the function for 'east' and "cos" for 'north' using those angles

arindameducationusc
 one year ago
Best ResponseYou've already chosen the best response.0@johnweldon1993 Can I give my argument here if you dont mind?

johnweldon1993
 one year ago
Best ResponseYou've already chosen the best response.1Yeah absolutely, that's why I said It's late it could be wrong. Always open to criticism

arindameducationusc
 one year ago
Best ResponseYou've already chosen the best response.0dw:1438833553890:dw See the black line I have drawn, As per the definition of displacement, we need that measurement. So, we need the length of the hypotenuse, i.e14^2+6^2

arindameducationusc
 one year ago
Best ResponseYou've already chosen the best response.0So, as per the displacement definition, if you see @YumYum247 's diagram. The triangles are not in 90 degrees. only the first hypotenuse can be used, not others as per the definition. What do you say @johnweldon1993 ?

johnweldon1993
 one year ago
Best ResponseYou've already chosen the best response.1Do you agree that every vector has both a 'x' and 'y' "and z irrelevant here" component?

YumYum247
 one year ago
Best ResponseYou've already chosen the best response.0oh my god, so do you use the x component and y component way????? i know how do to that way....

arindameducationusc
 one year ago
Best ResponseYou've already chosen the best response.0See the red line here, I guess this should be the displacement, ofcourse they have component x and y..... give me one minute ........ hmmmm

johnweldon1993
 one year ago
Best ResponseYou've already chosen the best response.1That should INDEED be the displacement My approach is to find how far over "x" and how far up "y" in order to find that red line being the hypotenuse \[\large Displacement = Red Line = \text{How far over}^2 + \text{How far up}^2\]

YumYum247
 one year ago
Best ResponseYou've already chosen the best response.0Thank you bunch of lumps of flesh and pile of dead skin cells, i really appreciated you help.... :")

johnweldon1993
 one year ago
Best ResponseYou've already chosen the best response.1haha no problem...let us know what you end up with!

arindameducationusc
 one year ago
Best ResponseYou've already chosen the best response.0We had a blackout... Sorry couldnot reply k, bye....

YumYum247
 one year ago
Best ResponseYou've already chosen the best response.0can someone please check my work, i had to figure out the average velocity and average speed too, see if i've done it correct. :")
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