if discriminant D=b^2-4ac>0 and a perfect square,then roots are real ,rational and different. if D>0 and not a perfect square then roots are real and irrational.
woah i didn't quite understand that..
for first D=b^2-4ac=6^2-4(1)(-16=36+64=100=10^2 what can you say now?
I'm sorry i thought you were suppose to just match the two top ones with the bottom and then explain why each one is which..
i have solved for f(x)
oh ok so the answer for the f(x) is d=6^2-4(1)(-16)=36+64=100=10^2
explanation i have given above ,you have to see. you see it is positive and a perfect square.
what about for g(x)?
sorry I'm bothering, ill give you the medal just please help with that last part..
can someone at least just explain the bottom half for me?