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anonymous
 one year ago
Classify the solutions of 1 over x plus 4, plus one half, equals 1 over x plus 4 as extraneous or nonextraneous
anonymous
 one year ago
Classify the solutions of 1 over x plus 4, plus one half, equals 1 over x plus 4 as extraneous or nonextraneous

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misty1212
 one year ago
Best ResponseYou've already chosen the best response.0lol there is either a solution, or there is not not sur what math teacher made up this "extraneous' nonsense

misty1212
 one year ago
Best ResponseYou've already chosen the best response.0\[\frac{1}{x+4}+\frac{1}{2}=\frac{1}{x+4}\]? is that the question?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0i just need help with the extraneous and non extraneous

misty1212
 one year ago
Best ResponseYou've already chosen the best response.0oh ok then lets think

misty1212
 one year ago
Best ResponseYou've already chosen the best response.0x is a variable, it can be anything but whatever it is on the left, it is the same on the right so if you add one half to a number, it is impossible to get the same number back there is NO SOLUTION

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0the answer is x= 4 but idk if its extraneous or not

misty1212
 one year ago
Best ResponseYou've already chosen the best response.0THE ANSWER IS NOT X = 4

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0then what is it? bc i followed the directions in the lesson

misty1212
 one year ago
Best ResponseYou've already chosen the best response.0ok fine, say \(x=4\) is "extraneous" if that will make your math teacher happy

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0do you know the difference between the two?

misty1212
 one year ago
Best ResponseYou've already chosen the best response.0\[\overbrace{\frac{1}{x+4}}^{\text{this}}+\frac{1}{2}=\overbrace{\frac{1}{x+4}}^{\text{is equal to this}}\]

misty1212
 one year ago
Best ResponseYou've already chosen the best response.0you cannot add one half to a number and get the same number back

misty1212
 one year ago
Best ResponseYou've already chosen the best response.0the not very bright math teacher who wants you not to think like a person, but do some steps to "solve" wants you to find that \(x=4\) but \(x\) cannot be \(4\) because a) that would make the denominator zero and b) there is NO SOLUTION

misty1212
 one year ago
Best ResponseYou've already chosen the best response.0therefore they want you to behave like a robot and say "the solution is \(x=4\) but it is "extraneous""

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0x = −4; extraneous x = −4; nonextraneous x = −8; extraneous x = −8; nonextraneous so out of these answer choices......its the first one?
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