Which polynomial function has a leading coefficient of 3 and roots –4, i, and 2, all with multiplicity 1? f(x) = 3(x + 4)(x – i)(x – 2) f(x) = (x – 3)(x + 4)(x – i)(x – 2) f(x) = (x – 3)(x + 4)(x – i)(x + i)(x – 2) f(x) = 3(x + 4)(x – i)(x + i)(x – 2)

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Which polynomial function has a leading coefficient of 3 and roots –4, i, and 2, all with multiplicity 1? f(x) = 3(x + 4)(x – i)(x – 2) f(x) = (x – 3)(x + 4)(x – i)(x – 2) f(x) = (x – 3)(x + 4)(x – i)(x + i)(x – 2) f(x) = 3(x + 4)(x – i)(x + i)(x – 2)

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At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.

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http://www.wolframalpha.com/input/?i=expand+3%28x%2B4%29%28x%5E2%2B1%29%28x-2%29
oh hold on
if it is supposed to be a real polynomial you have to go with the last one

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Other answers:

each factor is \((x-\text{ one of the zeros})\)
except if it should be real, then you need both \((x-i)\) and \((x+i)\) i would pick D
Thank you!!!
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imaginary roots always occur in pairs.

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