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anonymous

  • one year ago

Which polynomial function has a leading coefficient of 3 and roots –4, i, and 2, all with multiplicity 1? f(x) = 3(x + 4)(x – i)(x – 2) f(x) = (x – 3)(x + 4)(x – i)(x – 2) f(x) = (x – 3)(x + 4)(x – i)(x + i)(x – 2) f(x) = 3(x + 4)(x – i)(x + i)(x – 2)

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  1. misty1212
    • one year ago
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    http://www.wolframalpha.com/input/?i=expand+3%28x%2B4%29%28x%5E2%2B1%29%28x-2%29

  2. misty1212
    • one year ago
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    oh hold on

  3. misty1212
    • one year ago
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    if it is supposed to be a real polynomial you have to go with the last one

  4. misty1212
    • one year ago
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    each factor is \((x-\text{ one of the zeros})\)

  5. misty1212
    • one year ago
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    except if it should be real, then you need both \((x-i)\) and \((x+i)\) i would pick D

  6. anonymous
    • one year ago
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    Thank you!!!

  7. misty1212
    • one year ago
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    \[\color\magenta\heartsuit\]

  8. anonymous
    • one year ago
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    imaginary roots always occur in pairs.

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