A community for students.
Here's the question you clicked on:
 0 viewing
anonymous
 one year ago
Which quadratic equation is equivalent to (x + 2)2 + 5(x + 2) – 6 = 0?
(u + 2)^2 + 5(u + 2) – 6 = 0 where u = (x – 2)
u^2 + 4 + 5u – 6 = 0 where u = (x – 2)
u^2 + 5u – 6 = 0 where u = (x + 2)
u^2 + u – 6 = 0 where u = (x + 2)
anonymous
 one year ago
Which quadratic equation is equivalent to (x + 2)2 + 5(x + 2) – 6 = 0? (u + 2)^2 + 5(u + 2) – 6 = 0 where u = (x – 2) u^2 + 4 + 5u – 6 = 0 where u = (x – 2) u^2 + 5u – 6 = 0 where u = (x + 2) u^2 + u – 6 = 0 where u = (x + 2)

This Question is Closed

misty1212
 one year ago
Best ResponseYou've already chosen the best response.1\[ (x + 2)^2 + 5(x + 2) – 6 = 0\] put \(\color{red}u=x+2\) get \[\huge\color{red}u^2+5\color{red}u6=0\]

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0or just go with C since it is always C

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0When in doubt pick C lol.

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Which equation is quadratic in form? 4(x – 2)2 + 3x – 2 + 1 = 0 8x^5 + 4x^3 + 1 = 0 10x^8 + 7x^4 + 1 = 0 9x^16 + 6x^4 + 1 = 0

misty1212
 one year ago
Best ResponseYou've already chosen the best response.1quadratic means hmm this is a trick

misty1212
 one year ago
Best ResponseYou've already chosen the best response.1i think they want you to say \(10x^8 + 7x^4 + 1 = 0\) is in "quadratic form" because you can make \(u=x^4\) and it becomes \[10u^2+7u+1=0\]

misty1212
 one year ago
Best ResponseYou've already chosen the best response.1the first one is in fact a quadratic equation, but C (as usual C) is in "quadratic form" go with that one

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0What substitution should be used to rewrite 4x^12 – 5x6 – 14 = 0 as a quadratic equation? u = x^2 u = x^3 u = x^6 u = x^12

misty1212
 one year ago
Best ResponseYou've already chosen the best response.1the middle term is has \(x^6\) so you can use \(u=x^6\)

misty1212
 one year ago
Best ResponseYou've already chosen the best response.1ooh what a surprise, C again...

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Thank you! What substitution should be used to rewrite 16(x^3 + 1)^2 – 22(x^3 + 1) – 3 = 0 as a quadratic equation? u = (x^3) u = (x^3 + 1) u = (x^3 + 1)^2 u = (x^3 + 1)^3

misty1212
 one year ago
Best ResponseYou've already chosen the best response.1you can use \(u=(x^3+1)\)

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0What are the solutions of the equation x^4 + 3x^2 + 2 = 0? Use u substitution to solve.

misty1212
 one year ago
Best ResponseYou've already chosen the best response.1\[ x^4 + 3x^2 + 2 = 0\] put \[u=x^2\] get \[y=u^2+3u+2=0\] or \[(u+1)(u+2)=0\] but there will be no real solution only complex ones

misty1212
 one year ago
Best ResponseYou've already chosen the best response.1is there a typo in the question?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0A.) ±i (sqrt)2 and x = ±1 B) ±i (sqrt)2 and x = ±i C)±(sqrt)2 and x = ±i D)± (sqrt)2 and x = ±1

misty1212
 one year ago
Best ResponseYou've already chosen the best response.1oh they allow complex solutions ok

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0yes it just took me a minute to type out! :]

misty1212
 one year ago
Best ResponseYou've already chosen the best response.1\[u+1=00\\ u=1\\ ^2=1\\ x=\pm i\] is one pair

misty1212
 one year ago
Best ResponseYou've already chosen the best response.1the other is \(x=\pm\sqrt{2}i\)

misty1212
 one year ago
Best ResponseYou've already chosen the best response.1looks like they put the \(i\) first , go with B

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0What are the solutions of the equation x^4 – 5x^2 – 14 = 0? Use factoring to solve. Same as before.

misty1212
 one year ago
Best ResponseYou've already chosen the best response.1yeah same as before \[u=x^2\] get \[u^25u14=0\] or \[(u7)(u+2)=0\] so \[u=7\]or \[u=2\]

misty1212
 one year ago
Best ResponseYou've already chosen the best response.1then \[x^2=7\\ x=\pm\sqrt7\] or \[x^2=2\\ x=\pm\sqrt{2}i\]

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0yayy thats what i had :)
Ask your own question
Sign UpFind more explanations on OpenStudy
Your question is ready. Sign up for free to start getting answers.
spraguer
(Moderator)
5
→ View Detailed Profile
is replying to Can someone tell me what button the professor is hitting...
23
 Teamwork 19 Teammate
 Problem Solving 19 Hero
 Engagement 19 Mad Hatter
 You have blocked this person.
 ✔ You're a fan Checking fan status...
Thanks for being so helpful in mathematics. If you are getting quality help, make sure you spread the word about OpenStudy.