anonymous
  • anonymous
6x^2-18x-60 Could someone help me out with this? I'm taking two math classes at once, so I'm getting things mixed up. The instructions for it say "factor completely, or state that the polynomial is prime"
Mathematics
  • Stacey Warren - Expert brainly.com
Hey! We 've verified this expert answer for you, click below to unlock the details :)
SOLVED
At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.
schrodinger
  • schrodinger
I got my questions answered at brainly.com in under 10 minutes. Go to brainly.com now for free help!
anonymous
  • anonymous
So, this isn't a prime polynomial. It can be factored/simplified further. First, find the GFC of the equation. The GFC includes the largest number and highest degree of x that can be divided equally in the equation. Once you have the GFC, factor it out. Put the GFC as the first term and then divide each term by it.
anonymous
  • anonymous
The GCF is 6, so it'd be like 6(x^2-3x-10) right?
anonymous
  • anonymous
Yes, correct! The term in the parenthesis can be factored even further though. Which two numbers add up to -3 and multiply to -10?

Looking for something else?

Not the answer you are looking for? Search for more explanations.

More answers

anonymous
  • anonymous
-5 and 2
anonymous
  • anonymous
Those are your solutions to the equation, which is (x - 5)(x + 2). The fully simplified equation is 6(x - 5)(x + 2).
anonymous
  • anonymous
Ohhh, that makes more sense than the answers I was coming up with! haha thank you!
anonymous
  • anonymous
You're welcome

Looking for something else?

Not the answer you are looking for? Search for more explanations.