x intercept when y = 0 x-a is a factor x = a so factors are (x+0.5) (x-2) vertex (0.5, 4) (h, k) vertex form of parabola a(x-h)^2 + k a(x-0.5)^2 + 4 = 0
sorry was still trying to get to the correct function for function 2 so i don't know
Functions 1 and 2 are shown below: Function 1: f(x) = −3x2 + 2 A graph of a parabola with x intercepts of negative 0.5, 0 and 2, 0 and a vertex of 0.5, 4 is shown.
Function 2: A graph of a parabola with x intercepts of negative 0.5, 0 and 2, 0 and a vertex of 0.5, 4 is shown.
so what is the expression for the graph shown function 2?
it just shows a graph
its maximum is at about 4
yea it looks something like that
what is the function? the x value of the vertex is the line of symmetry for the parabola at x = 1/2 -1/2, 0 and 2,0 are not equal distance
ill stick with function 2. thank you for your time :)
well you are welcome