This year, 75% of the graduating class of Harriet Tubman High School had taken at least 8 math courses. Of the remaining class members, 60% had taken 6 or 7 math courses. What percent of the graduating class had taken fewer than 6 math courses? PLEASE EXPLAIN WELL, thank you very much!
Stacey Warren - Expert brainly.com
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If 75% of the class had taken at least 8 math courses, then that means the other 25% had taken less than 8. Also, if 60% had taken 6 or 7 math courses, then that leaves the other 40% to have taken 5 or less math courses. 60% of that 25% had 6+ classes that leaves 40% of that 25% with fewer than 6 classes.
It would be easier to solve/work with if the numbers are actually known. You just need to calculate the 25% of the 75%. The 25% of the class is who took fewer than 8. But it's also said that 60% took 6 or 7 classes. The rest of the 40% (taken from the 60) must have had 6 classes or less. Take 25% and turn it into 25. Let's say that 25% of the graduating class is 25. Multiply 25 by 40% to receive the percentage of the graduating class who took less than 6 math courses.
25 • 40% = 10... So it's 10 percent right? That's what I got? Also how you get 25 % that's where I get kind of confuse? Sorry. I'm just confuse. Thank you so much for your help! Means a lot!
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Yep... 10% of the graduating class took less than 6 classes. Also, I got 25% from 100%-75%. It's mentioned that 75% of the graduating class took 8 classes, so that meant that the rest of the class, which was the 25% took less than 8.
Oh okay... So you also did the same to the 60% you subtracted the 100% - 60% and got 40%. Okay. But how you get 100?
Sorry! For all these questions! I just wanna understand it and not just get the answer.
Hey, sorry for the late reply! I got 100 because of the 100%.