anonymous
  • anonymous
Need help! How does integral of sinx - cscx become -cosx?
Mathematics
katieb
  • katieb
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anonymous
  • anonymous
|dw:1438832459561:dw|
anonymous
  • anonymous
...does anyone know whats going on?
geerky42
  • geerky42
It doesn't.

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geerky42
  • geerky42
http://www.wolframalpha.com/input/?t=crmtb01&f=ob&i=integral%20of%20sin%20x%20-%20csc%20x
anonymous
  • anonymous
Well.. thats the answer in the back of the book buddy
geerky42
  • geerky42
Well, textbooks aren't perfect.
mathstudent55
  • mathstudent55
|dw:1438832964732:dw|
anonymous
  • anonymous
Okay, so let me just write down the original integral problem
anonymous
  • anonymous
|dw:1438833089151:dw|
anonymous
  • anonymous
So that was the original problem... and know Im trying to figure out how to get to the answer... which apparently is: sec(x)+c
anonymous
  • anonymous
*now
anonymous
  • anonymous
wait, whyd you delete it?!
geerky42
  • geerky42
HINT: Use u-substitution here. \[\int \dfrac{\sin x}{\cos^2 x} ~\mathrm dx\]
anonymous
  • anonymous
We havent learned that
geerky42
  • geerky42
what do you know so far?
anonymous
  • anonymous
We have never applied U substitution method so far in class
geerky42
  • geerky42
What method did you learn?
anonymous
  • anonymous
Just evaluating the integral normally
geerky42
  • geerky42
Ok, do you use integral table or something?
geerky42
  • geerky42
You do know that \(\dfrac{\sin x}{\cos^2x} = \tan x\sec x\)?
anonymous
  • anonymous
wouldnt it be adding tanx + sec x
anonymous
  • anonymous
Oh no, youre right
geerky42
  • geerky42
So can you evaluate integral now?
anonymous
  • anonymous
The answer is clear now
anonymous
  • anonymous
thanks
geerky42
  • geerky42
okay good.
geerky42
  • geerky42
no problem

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