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15 yards greater than the width = x(x+15) Is that to what it translates to?
Let Width = W and Length = W + 15 |dw:1438833371504:dw| If the area in total = 450 We have \[\large Length \times Width = 450\] \[\large (W+15) \times W = 450\] Solve for 'w' and then solve for 'l'
\[w^2+15w=450\] Would I have to move everything to the left side?
It would be a quadratic...so I should say so ^_^
Okie, hang on lol
I can use the quadratic equation or formula or whatever you call it, right?
I got 15. Is that correct?
Indeed...which would make the Length then...
OMG I CANNOT BELIEVE I'M FINALLY UNDERSTANDING THIS HAHAH! THIS IS UNBELIEVABLE!!! Oh, I was going to ask about that... Where would I plug it back into?
Lol told you you were smart :P And just re-read the first sentence of your question :)
Plug it back into 15*x??? LOL HELP!:)
"The length is 15 greater than the width" Didnt we just solve for the width? ;P
You love me if you help me haha.
Lol well then...looks like I love you <3 XD
Lol, haha<3 I need some sidetracking for a bit LOL. Anyways.... (15+15) *15? I can't think lol..
Lol I do believe you are overthinking this hun So Width = 15 Length = 15 greater than the Width So quite literally...Length = 15 greater than 15....15 + 15 = ?
OMG hahha. I am. I thought it was something crazy like the formula haha. I'm so stupid lol. Ok.. It's 30 lol. I knew it was something around there but fear attacked me and I lost lol.
Lol just breathe :P So yes we found Length = 30 and Width = 15 Just to double check...30 x 15 = 450? Indeed it does...so you are correct
I'm trying but I'm running out of oxygen haha. Anyways, yes. It does.
"Fans you" give her room! lol you are done "my love" <3 :P
LOL haha. Ok, I have a similar one but I'll open a new question.. I'm not sure if I solved the first few steps correctly, so I may need your guidance again...
Of course :)