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YanaSidlinskiy
 one year ago
A rectangular parking lot has a length that is 15 yards greater than the width. The area of the parking lot is 450 square yards. Find the length and the width. Use the formula, are = length * width.
YanaSidlinskiy
 one year ago
A rectangular parking lot has a length that is 15 yards greater than the width. The area of the parking lot is 450 square yards. Find the length and the width. Use the formula, are = length * width.

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YanaSidlinskiy
 one year ago
Best ResponseYou've already chosen the best response.015 yards greater than the width = x(x+15) Is that to what it translates to?

johnweldon1993
 one year ago
Best ResponseYou've already chosen the best response.1Let Width = W and Length = W + 15 dw:1438833371504:dw If the area in total = 450 We have \[\large Length \times Width = 450\] \[\large (W+15) \times W = 450\] Solve for 'w' and then solve for 'l'

YanaSidlinskiy
 one year ago
Best ResponseYou've already chosen the best response.0\[w^2+15w=450\] Would I have to move everything to the left side?

johnweldon1993
 one year ago
Best ResponseYou've already chosen the best response.1It would be a quadratic...so I should say so ^_^

YanaSidlinskiy
 one year ago
Best ResponseYou've already chosen the best response.0Okie, hang on lol

YanaSidlinskiy
 one year ago
Best ResponseYou've already chosen the best response.0I can use the quadratic equation or formula or whatever you call it, right?

YanaSidlinskiy
 one year ago
Best ResponseYou've already chosen the best response.0I got 15. Is that correct?

johnweldon1993
 one year ago
Best ResponseYou've already chosen the best response.1Indeed...which would make the Length then...

YanaSidlinskiy
 one year ago
Best ResponseYou've already chosen the best response.0OMG I CANNOT BELIEVE I'M FINALLY UNDERSTANDING THIS HAHAH! THIS IS UNBELIEVABLE!!! Oh, I was going to ask about that... Where would I plug it back into?

johnweldon1993
 one year ago
Best ResponseYou've already chosen the best response.1Lol told you you were smart :P And just reread the first sentence of your question :)

YanaSidlinskiy
 one year ago
Best ResponseYou've already chosen the best response.0Plug it back into 15*x??? LOL HELP!:)

johnweldon1993
 one year ago
Best ResponseYou've already chosen the best response.1"The length is 15 greater than the width" Didnt we just solve for the width? ;P

YanaSidlinskiy
 one year ago
Best ResponseYou've already chosen the best response.0You love me if you help me haha.

johnweldon1993
 one year ago
Best ResponseYou've already chosen the best response.1Lol well then...looks like I love you <3 XD

YanaSidlinskiy
 one year ago
Best ResponseYou've already chosen the best response.0Lol, haha<3 I need some sidetracking for a bit LOL. Anyways.... (15+15) *15? I can't think lol..

johnweldon1993
 one year ago
Best ResponseYou've already chosen the best response.1Lol I do believe you are overthinking this hun So Width = 15 Length = 15 greater than the Width So quite literally...Length = 15 greater than 15....15 + 15 = ?

YanaSidlinskiy
 one year ago
Best ResponseYou've already chosen the best response.0OMG hahha. I am. I thought it was something crazy like the formula haha. I'm so stupid lol. Ok.. It's 30 lol. I knew it was something around there but fear attacked me and I lost lol.

johnweldon1993
 one year ago
Best ResponseYou've already chosen the best response.1Lol just breathe :P So yes we found Length = 30 and Width = 15 Just to double check...30 x 15 = 450? Indeed it does...so you are correct

YanaSidlinskiy
 one year ago
Best ResponseYou've already chosen the best response.0I'm trying but I'm running out of oxygen haha. Anyways, yes. It does.

johnweldon1993
 one year ago
Best ResponseYou've already chosen the best response.1"Fans you" give her room! lol you are done "my love" <3 :P

YanaSidlinskiy
 one year ago
Best ResponseYou've already chosen the best response.0LOL haha. Ok, I have a similar one but I'll open a new question.. I'm not sure if I solved the first few steps correctly, so I may need your guidance again...
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