## anonymous one year ago help!!!!!!!!!!!!!!!!!!

1. anonymous

Olivia rolls two fair number cubes numbered from 1 to 6. She first defines the sample space as shown below: (1, 1), (1, 2), (1, 3), (1, 4), (1, 5), (1, 6) (2, 1), (2, 2), (2, 3), (2, 4), (2, 5), (2, 6) (3, 1), (3, 2), (3, 3), (3, 4), (3, 5), (3, 6) (4, 1), (4, 2), (4, 3), (4, 4), (4, 5), (4, 6) (5, 1), (5, 2), (5, 3), (5, 4), (5, 5), (5, 6) (6, 1), (6, 2), (6, 3), (6, 4), (6, 5), (6, 6) Based on the sample space, what is the probability of getting a total of 10?

2. anonymous

First off, count how many ordered pairs there are in total

3. anonymous

Then, count how many of those ordered pairs have a sum of 10

4. anonymous

Lastly, write it as a fraction and simplify

5. anonymous

can you help me

6. anonymous

Sure!

7. mathstudent55

How many outcomes have a sum of 10? $$(1, 1), (1, 2), (1, 3), (1, 4), (1, 5), (1, 6)$$ $$(2, 1), (2, 2), (2, 3), (2, 4), (2, 5), (2, 6)$$ $$(3, 1), (3, 2), (3, 3), (3, 4), (3, 5), (3, 6)$$ $$(4, 1), (4, 2), (4, 3), (4, 4), (4, 5), \color{red}{(4, 6)}$$ $$(5, 1), (5, 2), (5, 3), (5, 4), \color{red}{(5, 5)}, (5, 6)$$ $$(6, 1), (6, 2), (6, 3), \color{red}{(6, 4)}, (6, 5), (6, 6)$$

8. anonymous

There are 36 ordered pairs total

9. anonymous

yes

10. anonymous

3 of which have a sum of 10

11. anonymous

$\frac{ 3 }{ 36 }$

12. anonymous

13. anonymous

thanks

14. anonymous

You're welcome!