anonymous
  • anonymous
help!!!!!!!!!!!!!!!!!!
Mathematics
schrodinger
  • schrodinger
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anonymous
  • anonymous
Olivia rolls two fair number cubes numbered from 1 to 6. She first defines the sample space as shown below: (1, 1), (1, 2), (1, 3), (1, 4), (1, 5), (1, 6) (2, 1), (2, 2), (2, 3), (2, 4), (2, 5), (2, 6) (3, 1), (3, 2), (3, 3), (3, 4), (3, 5), (3, 6) (4, 1), (4, 2), (4, 3), (4, 4), (4, 5), (4, 6) (5, 1), (5, 2), (5, 3), (5, 4), (5, 5), (5, 6) (6, 1), (6, 2), (6, 3), (6, 4), (6, 5), (6, 6) Based on the sample space, what is the probability of getting a total of 10?
anonymous
  • anonymous
First off, count how many ordered pairs there are in total
anonymous
  • anonymous
Then, count how many of those ordered pairs have a sum of 10

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anonymous
  • anonymous
Lastly, write it as a fraction and simplify
anonymous
  • anonymous
can you help me
anonymous
  • anonymous
Sure!
mathstudent55
  • mathstudent55
How many outcomes have a sum of 10? \((1, 1), (1, 2), (1, 3), (1, 4), (1, 5), (1, 6)\) \( (2, 1), (2, 2), (2, 3), (2, 4), (2, 5), (2, 6)\) \( (3, 1), (3, 2), (3, 3), (3, 4), (3, 5), (3, 6)\) \( (4, 1), (4, 2), (4, 3), (4, 4), (4, 5), \color{red}{(4, 6)}\) \( (5, 1), (5, 2), (5, 3), (5, 4), \color{red}{(5, 5)}, (5, 6)\) \( (6, 1), (6, 2), (6, 3), \color{red}{(6, 4)}, (6, 5), (6, 6)\)
anonymous
  • anonymous
There are 36 ordered pairs total
anonymous
  • anonymous
yes
anonymous
  • anonymous
3 of which have a sum of 10
anonymous
  • anonymous
\[\frac{ 3 }{ 36 }\]
anonymous
  • anonymous
Simplify that and you have your answer
anonymous
  • anonymous
thanks
anonymous
  • anonymous
You're welcome!

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