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anonymous

  • one year ago

help!!!!!!!!!!!!!!!!!!

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  1. anonymous
    • one year ago
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    Olivia rolls two fair number cubes numbered from 1 to 6. She first defines the sample space as shown below: (1, 1), (1, 2), (1, 3), (1, 4), (1, 5), (1, 6) (2, 1), (2, 2), (2, 3), (2, 4), (2, 5), (2, 6) (3, 1), (3, 2), (3, 3), (3, 4), (3, 5), (3, 6) (4, 1), (4, 2), (4, 3), (4, 4), (4, 5), (4, 6) (5, 1), (5, 2), (5, 3), (5, 4), (5, 5), (5, 6) (6, 1), (6, 2), (6, 3), (6, 4), (6, 5), (6, 6) Based on the sample space, what is the probability of getting a total of 10?

  2. anonymous
    • one year ago
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    First off, count how many ordered pairs there are in total

  3. anonymous
    • one year ago
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    Then, count how many of those ordered pairs have a sum of 10

  4. anonymous
    • one year ago
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    Lastly, write it as a fraction and simplify

  5. anonymous
    • one year ago
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    can you help me

  6. anonymous
    • one year ago
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    Sure!

  7. mathstudent55
    • one year ago
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    How many outcomes have a sum of 10? \((1, 1), (1, 2), (1, 3), (1, 4), (1, 5), (1, 6)\) \( (2, 1), (2, 2), (2, 3), (2, 4), (2, 5), (2, 6)\) \( (3, 1), (3, 2), (3, 3), (3, 4), (3, 5), (3, 6)\) \( (4, 1), (4, 2), (4, 3), (4, 4), (4, 5), \color{red}{(4, 6)}\) \( (5, 1), (5, 2), (5, 3), (5, 4), \color{red}{(5, 5)}, (5, 6)\) \( (6, 1), (6, 2), (6, 3), \color{red}{(6, 4)}, (6, 5), (6, 6)\)

  8. anonymous
    • one year ago
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    There are 36 ordered pairs total

  9. anonymous
    • one year ago
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    yes

  10. anonymous
    • one year ago
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    3 of which have a sum of 10

  11. anonymous
    • one year ago
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    \[\frac{ 3 }{ 36 }\]

  12. anonymous
    • one year ago
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    Simplify that and you have your answer

  13. anonymous
    • one year ago
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    thanks

  14. anonymous
    • one year ago
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    You're welcome!

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