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anonymous
 one year ago
For f(x) = 0.01(2)x, find the average rate of change from x = 3 to x = 8.
A.0.08
B.0.496
C.2.48
D.5
anonymous
 one year ago
For f(x) = 0.01(2)x, find the average rate of change from x = 3 to x = 8. A.0.08 B.0.496 C.2.48 D.5

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anonymous
 one year ago
Best ResponseYou've already chosen the best response.0The average rate of change is given by: \[\frac{f(x_1)f(x_2)}{x_1x_2}\]

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Here, \(x_1=3\) and \(x_2=8\)

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0okay can u explain it more

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0dw:1438834225000:dw The average rate of change is the inclination of the line passing through the points (x1, f(x1)) and (x2, f(x2))

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0o okay would my answer be C. ?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0You function if \[f(x)=0.01(2)^x\]

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0\(f(3)=0.01(2)^3 = 0.08\)

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0do the same for \(f(8)\) and calculate the average rate of change: \[\frac{f(3)f(8)}{38}\]

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Ok, if you face any problem, just say

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0can u help me with another problem

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Identify the domain of the exponential function shown in the following graph: A curve runs just above the x axis through the second quadrant, passes through point 0 comma 1 and continues off screen near 1 comma 12. all real numbers all positive numbers 1 ≤ x ≤ 30 all integers

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0http://paec.flvs.net/webdav/assessment_images/educator_algebraI_v20/08_06_01a_05a.gif

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0The link is not working

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0http://paec.flvs.net/webdav/assessment_images/educator_algebraI_v20/08_06_01a_05a.gif

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Still not working, but based on teh description, it only takes positive values

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0So, if i would say that the domain is all positive numbers. Although I'm not 100% sure, since I can't see the graph

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0okay i will try it thx tho

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0do u have time for one more
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