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YanaSidlinskiy

  • one year ago

I LOVE MATH!

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  1. johnweldon1993
    • one year ago
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    Lol you love math? :P

  2. YanaSidlinskiy
    • one year ago
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    I'm factoring out greatest common factors for this one:\[6x^3-8x^2+10x\]\[2x(3x^2-4x+5)\] That's what I got.. Is it right?

  3. YanaSidlinskiy
    • one year ago
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    Yeah I definitely do. Can't you tell? lol;)

  4. johnweldon1993
    • one year ago
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    Perfect! and oh of course ;P

  5. YanaSidlinskiy
    • one year ago
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    Lol. yay haha. Factor by grouping: \[3x^2-6xy-4x+8y\]

  6. YanaSidlinskiy
    • one year ago
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    I haven't got my answer yet but I'm working on it lol.

  7. johnweldon1993
    • one year ago
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    Tell me when you do :D

  8. YanaSidlinskiy
    • one year ago
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    Ok, well for the first half I have 3x(x-2y)..... Blah...

  9. johnweldon1993
    • one year ago
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    Perfect....and the next half?

  10. YanaSidlinskiy
    • one year ago
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    For the second half.. I have: 4(-x+2y)

  11. YanaSidlinskiy
    • one year ago
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    Please tell me it's right lol.

  12. YanaSidlinskiy
    • one year ago
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    WAIT.

  13. YanaSidlinskiy
    • one year ago
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    LOL.

  14. YanaSidlinskiy
    • one year ago
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    STOP>

  15. YanaSidlinskiy
    • one year ago
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    I think I know what you're gonna say haha!

  16. YanaSidlinskiy
    • one year ago
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    WAIT. PAUSE LOL>

  17. johnweldon1993
    • one year ago
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    Lol I'll wait ;P

  18. YanaSidlinskiy
    • one year ago
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    It's the same thing hahaa;)

  19. YanaSidlinskiy
    • one year ago
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    -4(x-2y)

  20. johnweldon1993
    • one year ago
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    There we go :P But what next? O.o

  21. YanaSidlinskiy
    • one year ago
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    Idk you tell me haha

  22. johnweldon1993
    • one year ago
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    Lol so we have \[\large 3x(x - 2y) - 4(x - 2y)\] Since they both have a (x - 2y) in common...we factor that out...and write this as \[\large (3x - 4)(x - 2y)\]

  23. YanaSidlinskiy
    • one year ago
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    Ohh yeah. Duhh I forgot lol. Thanks for the reminder.

  24. johnweldon1993
    • one year ago
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    Haha oh of course that's what I'm here for ;P

  25. YanaSidlinskiy
    • one year ago
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    Hhaa, lol. I honestly can't explain how happy I am that you're on and you could help me LOL!

  26. johnweldon1993
    • one year ago
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    Well I had to cuz I love you remember <3 ;D lol No I like helping you cuz you dont bug me :P

  27. YanaSidlinskiy
    • one year ago
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    \[x^2-5x+4\] So I'm supposed to be factoring this out... Haven't done it but I'll give it a shot lol. Ohh yeah hhaa. Duhh<3 Are you sure I don't? I feel like I am haha.

  28. YanaSidlinskiy
    • one year ago
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    I'd set it to 0 right?

  29. johnweldon1993
    • one year ago
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    Lol nope you do all the work and I sit here and wait ;P And yes set it equal to 0

  30. YanaSidlinskiy
    • one year ago
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    Hha, ok lol. Ok: So I have this so far: \[\frac{ -(-5)\pm \sqrt{(-5)^2-4(1)(4)} }{ 2(1) }\]

  31. johnweldon1993
    • one year ago
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    mmhmm....continue :)

  32. YanaSidlinskiy
    • one year ago
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    I got prime. Is it right?

  33. johnweldon1993
    • one year ago
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    Huh? \[\large \frac{5 \pm \sqrt{9}}{2}\] is what I get

  34. YanaSidlinskiy
    • one year ago
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    Well 4*-4 = -16 And -5*-5=25 and I added that and got 41...

  35. johnweldon1993
    • one year ago
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    25 + -16 would be subtraction :)

  36. YanaSidlinskiy
    • one year ago
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    Well, I thought like if there's something like this: 25-(-16)... You would add...

  37. YanaSidlinskiy
    • one year ago
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    OH WAIT. THAT'S FOR ADDITION right?

  38. YanaSidlinskiy
    • one year ago
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    Or something idk...

  39. johnweldon1993
    • one year ago
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    No you are correct...if it were 25 - (-16) it would be 25 + 16 however here we have \[\large \sqrt{(-5)^2 - 4(1)(4)}\rightarrow \sqrt{25 - (16)} = \sqrt{9}=3\]

  40. YanaSidlinskiy
    • one year ago
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    Ok, I see where you're getting that from..

  41. johnweldon1993
    • one year ago
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    Good ^_^ so then yes we have \[\large \frac{5 \pm 3}{2}\]

  42. YanaSidlinskiy
    • one year ago
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    So the -4 is positive right? I'd read the 4 as a positive sign and the negative sign would be read to subtract right?

  43. YanaSidlinskiy
    • one year ago
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    I got 4,1

  44. johnweldon1993
    • one year ago
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    Well just take it part by part... \[\large \sqrt{(-5)^2 - \color\red{(4(1)(4))}}\] focus on on the red first, dont even worry about that ''-" sign right now \[\large \sqrt{25 - (16) }\]

  45. johnweldon1993
    • one year ago
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    And yes 4 and 1 would be correct So now...we know these are the roots of your polynomial We write them as \[\large (x - 4)(x-1) = 0\] And that is the factored form of it "why did it change to both being "minus"? Well because look at the equation...equal to 0 we want to be able to plug in either 4 or 1 into an equation and get 0....thus...we have that :)

  46. YanaSidlinskiy
    • one year ago
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    Ok, makes total sense lol.

  47. johnweldon1993
    • one year ago
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    does it really?

  48. YanaSidlinskiy
    • one year ago
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    Yeah I think haha. I may say something stupid right now cuz it's 1:31am..

  49. johnweldon1993
    • one year ago
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    Lol same here :P

  50. YanaSidlinskiy
    • one year ago
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    I'm a little cranky cuz I only got 3hrs of sleep last night. Haha. awesome!

  51. johnweldon1993
    • one year ago
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    Uh oh...get some sleep love :P

  52. YanaSidlinskiy
    • one year ago
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    Ik, but it's hard in cramming this homework and a final exam on campus tomorrow..

  53. YanaSidlinskiy
    • one year ago
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    If a polynomial does not factor out it'd be a prime right? cuz I'm asked to factor out 81x^2-1 But I get: 1(81x^2-1)

  54. johnweldon1993
    • one year ago
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    right, its just prime if nothing can be taken out

  55. YanaSidlinskiy
    • one year ago
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    okie. At least I got the last question right haha. There's more but I'll finish everything up tomorrow once I get up in like 3hrs... Goodnight! Sleep tight;)

  56. johnweldon1993
    • one year ago
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    Sleep tight hun ;)

  57. YanaSidlinskiy
    • one year ago
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    Hha, thanks lol ;) Anywho.. Audios!

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