I LOVE MATH!

- YanaSidlinskiy

I LOVE MATH!

- Stacey Warren - Expert brainly.com

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- chestercat

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- johnweldon1993

Lol you love math? :P

- YanaSidlinskiy

I'm factoring out greatest common factors for this one:\[6x^3-8x^2+10x\]\[2x(3x^2-4x+5)\] That's what I got.. Is it right?

- YanaSidlinskiy

Yeah I definitely do. Can't you tell? lol;)

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## More answers

- johnweldon1993

Perfect! and oh of course ;P

- YanaSidlinskiy

Lol. yay haha. Factor by grouping: \[3x^2-6xy-4x+8y\]

- YanaSidlinskiy

I haven't got my answer yet but I'm working on it lol.

- johnweldon1993

Tell me when you do :D

- YanaSidlinskiy

Ok, well for the first half I have
3x(x-2y)..... Blah...

- johnweldon1993

Perfect....and the next half?

- YanaSidlinskiy

For the second half.. I have:
4(-x+2y)

- YanaSidlinskiy

Please tell me it's right lol.

- YanaSidlinskiy

WAIT.

- YanaSidlinskiy

LOL.

- YanaSidlinskiy

STOP>

- YanaSidlinskiy

I think I know what you're gonna say haha!

- YanaSidlinskiy

WAIT. PAUSE LOL>

- johnweldon1993

Lol I'll wait ;P

- YanaSidlinskiy

It's the same thing hahaa;)

- YanaSidlinskiy

-4(x-2y)

- johnweldon1993

There we go :P
But what next? O.o

- YanaSidlinskiy

Idk you tell me haha

- johnweldon1993

Lol so we have
\[\large 3x(x - 2y) - 4(x - 2y)\]
Since they both have a (x - 2y) in common...we factor that out...and write this as
\[\large (3x - 4)(x - 2y)\]

- YanaSidlinskiy

Ohh yeah. Duhh I forgot lol. Thanks for the reminder.

- johnweldon1993

Haha oh of course that's what I'm here for ;P

- YanaSidlinskiy

Hhaa, lol. I honestly can't explain how happy I am that you're on and you could help me LOL!

- johnweldon1993

Well I had to cuz I love you remember <3 ;D lol
No I like helping you cuz you dont bug me :P

- YanaSidlinskiy

\[x^2-5x+4\]
So I'm supposed to be factoring this out... Haven't done it but I'll give it a shot lol. Ohh yeah hhaa. Duhh<3 Are you sure I don't? I feel like I am haha.

- YanaSidlinskiy

I'd set it to 0 right?

- johnweldon1993

Lol nope you do all the work and I sit here and wait ;P
And yes set it equal to 0

- YanaSidlinskiy

Hha, ok lol. Ok: So I have this so far: \[\frac{ -(-5)\pm \sqrt{(-5)^2-4(1)(4)} }{ 2(1) }\]

- johnweldon1993

mmhmm....continue :)

- YanaSidlinskiy

I got prime. Is it right?

- johnweldon1993

Huh?
\[\large \frac{5 \pm \sqrt{9}}{2}\]
is what I get

- YanaSidlinskiy

Well 4*-4 = -16
And -5*-5=25 and I added that and got 41...

- johnweldon1993

25 + -16 would be subtraction :)

- YanaSidlinskiy

Well, I thought like if there's something like this:
25-(-16)... You would add...

- YanaSidlinskiy

OH WAIT. THAT'S FOR ADDITION right?

- YanaSidlinskiy

Or something idk...

- johnweldon1993

No you are correct...if it were 25 - (-16) it would be 25 + 16
however here we have
\[\large \sqrt{(-5)^2 - 4(1)(4)}\rightarrow \sqrt{25 - (16)} = \sqrt{9}=3\]

- YanaSidlinskiy

Ok, I see where you're getting that from..

- johnweldon1993

Good ^_^
so then yes we have
\[\large \frac{5 \pm 3}{2}\]

- YanaSidlinskiy

So the -4 is positive right? I'd read the 4 as a positive sign and the negative sign would be read to subtract right?

- YanaSidlinskiy

I got 4,1

- johnweldon1993

Well just take it part by part...
\[\large \sqrt{(-5)^2 - \color\red{(4(1)(4))}}\]
focus on on the red first, dont even worry about that ''-" sign right now
\[\large \sqrt{25 - (16) }\]

- johnweldon1993

And yes 4 and 1 would be correct
So now...we know these are the roots of your polynomial
We write them as
\[\large (x - 4)(x-1) = 0\]
And that is the factored form of it
"why did it change to both being "minus"?
Well because look at the equation...equal to 0
we want to be able to plug in either 4 or 1 into an equation and get 0....thus...we have that :)

- YanaSidlinskiy

Ok, makes total sense lol.

- johnweldon1993

does it really?

- YanaSidlinskiy

Yeah I think haha. I may say something stupid right now cuz it's 1:31am..

- johnweldon1993

Lol same here :P

- YanaSidlinskiy

I'm a little cranky cuz I only got 3hrs of sleep last night. Haha. awesome!

- johnweldon1993

Uh oh...get some sleep love :P

- YanaSidlinskiy

Ik, but it's hard in cramming this homework and a final exam on campus tomorrow..

- YanaSidlinskiy

If a polynomial does not factor out it'd be a prime right? cuz I'm asked to factor out
81x^2-1
But I get:
1(81x^2-1)

- johnweldon1993

right, its just prime if nothing can be taken out

- YanaSidlinskiy

okie. At least I got the last question right haha. There's more but I'll finish everything up tomorrow once I get up in like 3hrs... Goodnight! Sleep tight;)

- johnweldon1993

Sleep tight hun ;)

- YanaSidlinskiy

Hha, thanks lol ;) Anywho.. Audios!

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