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YanaSidlinskiy
 one year ago
I LOVE MATH!
YanaSidlinskiy
 one year ago
I LOVE MATH!

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johnweldon1993
 one year ago
Best ResponseYou've already chosen the best response.1Lol you love math? :P

YanaSidlinskiy
 one year ago
Best ResponseYou've already chosen the best response.1I'm factoring out greatest common factors for this one:\[6x^38x^2+10x\]\[2x(3x^24x+5)\] That's what I got.. Is it right?

YanaSidlinskiy
 one year ago
Best ResponseYou've already chosen the best response.1Yeah I definitely do. Can't you tell? lol;)

johnweldon1993
 one year ago
Best ResponseYou've already chosen the best response.1Perfect! and oh of course ;P

YanaSidlinskiy
 one year ago
Best ResponseYou've already chosen the best response.1Lol. yay haha. Factor by grouping: \[3x^26xy4x+8y\]

YanaSidlinskiy
 one year ago
Best ResponseYou've already chosen the best response.1I haven't got my answer yet but I'm working on it lol.

johnweldon1993
 one year ago
Best ResponseYou've already chosen the best response.1Tell me when you do :D

YanaSidlinskiy
 one year ago
Best ResponseYou've already chosen the best response.1Ok, well for the first half I have 3x(x2y)..... Blah...

johnweldon1993
 one year ago
Best ResponseYou've already chosen the best response.1Perfect....and the next half?

YanaSidlinskiy
 one year ago
Best ResponseYou've already chosen the best response.1For the second half.. I have: 4(x+2y)

YanaSidlinskiy
 one year ago
Best ResponseYou've already chosen the best response.1Please tell me it's right lol.

YanaSidlinskiy
 one year ago
Best ResponseYou've already chosen the best response.1I think I know what you're gonna say haha!

YanaSidlinskiy
 one year ago
Best ResponseYou've already chosen the best response.1WAIT. PAUSE LOL>

johnweldon1993
 one year ago
Best ResponseYou've already chosen the best response.1Lol I'll wait ;P

YanaSidlinskiy
 one year ago
Best ResponseYou've already chosen the best response.1It's the same thing hahaa;)

johnweldon1993
 one year ago
Best ResponseYou've already chosen the best response.1There we go :P But what next? O.o

YanaSidlinskiy
 one year ago
Best ResponseYou've already chosen the best response.1Idk you tell me haha

johnweldon1993
 one year ago
Best ResponseYou've already chosen the best response.1Lol so we have \[\large 3x(x  2y)  4(x  2y)\] Since they both have a (x  2y) in common...we factor that out...and write this as \[\large (3x  4)(x  2y)\]

YanaSidlinskiy
 one year ago
Best ResponseYou've already chosen the best response.1Ohh yeah. Duhh I forgot lol. Thanks for the reminder.

johnweldon1993
 one year ago
Best ResponseYou've already chosen the best response.1Haha oh of course that's what I'm here for ;P

YanaSidlinskiy
 one year ago
Best ResponseYou've already chosen the best response.1Hhaa, lol. I honestly can't explain how happy I am that you're on and you could help me LOL!

johnweldon1993
 one year ago
Best ResponseYou've already chosen the best response.1Well I had to cuz I love you remember <3 ;D lol No I like helping you cuz you dont bug me :P

YanaSidlinskiy
 one year ago
Best ResponseYou've already chosen the best response.1\[x^25x+4\] So I'm supposed to be factoring this out... Haven't done it but I'll give it a shot lol. Ohh yeah hhaa. Duhh<3 Are you sure I don't? I feel like I am haha.

YanaSidlinskiy
 one year ago
Best ResponseYou've already chosen the best response.1I'd set it to 0 right?

johnweldon1993
 one year ago
Best ResponseYou've already chosen the best response.1Lol nope you do all the work and I sit here and wait ;P And yes set it equal to 0

YanaSidlinskiy
 one year ago
Best ResponseYou've already chosen the best response.1Hha, ok lol. Ok: So I have this so far: \[\frac{ (5)\pm \sqrt{(5)^24(1)(4)} }{ 2(1) }\]

johnweldon1993
 one year ago
Best ResponseYou've already chosen the best response.1mmhmm....continue :)

YanaSidlinskiy
 one year ago
Best ResponseYou've already chosen the best response.1I got prime. Is it right?

johnweldon1993
 one year ago
Best ResponseYou've already chosen the best response.1Huh? \[\large \frac{5 \pm \sqrt{9}}{2}\] is what I get

YanaSidlinskiy
 one year ago
Best ResponseYou've already chosen the best response.1Well 4*4 = 16 And 5*5=25 and I added that and got 41...

johnweldon1993
 one year ago
Best ResponseYou've already chosen the best response.125 + 16 would be subtraction :)

YanaSidlinskiy
 one year ago
Best ResponseYou've already chosen the best response.1Well, I thought like if there's something like this: 25(16)... You would add...

YanaSidlinskiy
 one year ago
Best ResponseYou've already chosen the best response.1OH WAIT. THAT'S FOR ADDITION right?

YanaSidlinskiy
 one year ago
Best ResponseYou've already chosen the best response.1Or something idk...

johnweldon1993
 one year ago
Best ResponseYou've already chosen the best response.1No you are correct...if it were 25  (16) it would be 25 + 16 however here we have \[\large \sqrt{(5)^2  4(1)(4)}\rightarrow \sqrt{25  (16)} = \sqrt{9}=3\]

YanaSidlinskiy
 one year ago
Best ResponseYou've already chosen the best response.1Ok, I see where you're getting that from..

johnweldon1993
 one year ago
Best ResponseYou've already chosen the best response.1Good ^_^ so then yes we have \[\large \frac{5 \pm 3}{2}\]

YanaSidlinskiy
 one year ago
Best ResponseYou've already chosen the best response.1So the 4 is positive right? I'd read the 4 as a positive sign and the negative sign would be read to subtract right?

johnweldon1993
 one year ago
Best ResponseYou've already chosen the best response.1Well just take it part by part... \[\large \sqrt{(5)^2  \color\red{(4(1)(4))}}\] focus on on the red first, dont even worry about that ''" sign right now \[\large \sqrt{25  (16) }\]

johnweldon1993
 one year ago
Best ResponseYou've already chosen the best response.1And yes 4 and 1 would be correct So now...we know these are the roots of your polynomial We write them as \[\large (x  4)(x1) = 0\] And that is the factored form of it "why did it change to both being "minus"? Well because look at the equation...equal to 0 we want to be able to plug in either 4 or 1 into an equation and get 0....thus...we have that :)

YanaSidlinskiy
 one year ago
Best ResponseYou've already chosen the best response.1Ok, makes total sense lol.

johnweldon1993
 one year ago
Best ResponseYou've already chosen the best response.1does it really?

YanaSidlinskiy
 one year ago
Best ResponseYou've already chosen the best response.1Yeah I think haha. I may say something stupid right now cuz it's 1:31am..

johnweldon1993
 one year ago
Best ResponseYou've already chosen the best response.1Lol same here :P

YanaSidlinskiy
 one year ago
Best ResponseYou've already chosen the best response.1I'm a little cranky cuz I only got 3hrs of sleep last night. Haha. awesome!

johnweldon1993
 one year ago
Best ResponseYou've already chosen the best response.1Uh oh...get some sleep love :P

YanaSidlinskiy
 one year ago
Best ResponseYou've already chosen the best response.1Ik, but it's hard in cramming this homework and a final exam on campus tomorrow..

YanaSidlinskiy
 one year ago
Best ResponseYou've already chosen the best response.1If a polynomial does not factor out it'd be a prime right? cuz I'm asked to factor out 81x^21 But I get: 1(81x^21)

johnweldon1993
 one year ago
Best ResponseYou've already chosen the best response.1right, its just prime if nothing can be taken out

YanaSidlinskiy
 one year ago
Best ResponseYou've already chosen the best response.1okie. At least I got the last question right haha. There's more but I'll finish everything up tomorrow once I get up in like 3hrs... Goodnight! Sleep tight;)

johnweldon1993
 one year ago
Best ResponseYou've already chosen the best response.1Sleep tight hun ;)

YanaSidlinskiy
 one year ago
Best ResponseYou've already chosen the best response.1Hha, thanks lol ;) Anywho.. Audios!
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