## YanaSidlinskiy one year ago I LOVE MATH!

1. johnweldon1993

Lol you love math? :P

2. YanaSidlinskiy

I'm factoring out greatest common factors for this one:$6x^3-8x^2+10x$$2x(3x^2-4x+5)$ That's what I got.. Is it right?

3. YanaSidlinskiy

Yeah I definitely do. Can't you tell? lol;)

4. johnweldon1993

Perfect! and oh of course ;P

5. YanaSidlinskiy

Lol. yay haha. Factor by grouping: $3x^2-6xy-4x+8y$

6. YanaSidlinskiy

I haven't got my answer yet but I'm working on it lol.

7. johnweldon1993

Tell me when you do :D

8. YanaSidlinskiy

Ok, well for the first half I have 3x(x-2y)..... Blah...

9. johnweldon1993

Perfect....and the next half?

10. YanaSidlinskiy

For the second half.. I have: 4(-x+2y)

11. YanaSidlinskiy

Please tell me it's right lol.

12. YanaSidlinskiy

WAIT.

13. YanaSidlinskiy

LOL.

14. YanaSidlinskiy

STOP>

15. YanaSidlinskiy

I think I know what you're gonna say haha!

16. YanaSidlinskiy

WAIT. PAUSE LOL>

17. johnweldon1993

Lol I'll wait ;P

18. YanaSidlinskiy

It's the same thing hahaa;)

19. YanaSidlinskiy

-4(x-2y)

20. johnweldon1993

There we go :P But what next? O.o

21. YanaSidlinskiy

Idk you tell me haha

22. johnweldon1993

Lol so we have $\large 3x(x - 2y) - 4(x - 2y)$ Since they both have a (x - 2y) in common...we factor that out...and write this as $\large (3x - 4)(x - 2y)$

23. YanaSidlinskiy

Ohh yeah. Duhh I forgot lol. Thanks for the reminder.

24. johnweldon1993

Haha oh of course that's what I'm here for ;P

25. YanaSidlinskiy

Hhaa, lol. I honestly can't explain how happy I am that you're on and you could help me LOL!

26. johnweldon1993

Well I had to cuz I love you remember <3 ;D lol No I like helping you cuz you dont bug me :P

27. YanaSidlinskiy

$x^2-5x+4$ So I'm supposed to be factoring this out... Haven't done it but I'll give it a shot lol. Ohh yeah hhaa. Duhh<3 Are you sure I don't? I feel like I am haha.

28. YanaSidlinskiy

I'd set it to 0 right?

29. johnweldon1993

Lol nope you do all the work and I sit here and wait ;P And yes set it equal to 0

30. YanaSidlinskiy

Hha, ok lol. Ok: So I have this so far: $\frac{ -(-5)\pm \sqrt{(-5)^2-4(1)(4)} }{ 2(1) }$

31. johnweldon1993

mmhmm....continue :)

32. YanaSidlinskiy

I got prime. Is it right?

33. johnweldon1993

Huh? $\large \frac{5 \pm \sqrt{9}}{2}$ is what I get

34. YanaSidlinskiy

Well 4*-4 = -16 And -5*-5=25 and I added that and got 41...

35. johnweldon1993

25 + -16 would be subtraction :)

36. YanaSidlinskiy

Well, I thought like if there's something like this: 25-(-16)... You would add...

37. YanaSidlinskiy

OH WAIT. THAT'S FOR ADDITION right?

38. YanaSidlinskiy

Or something idk...

39. johnweldon1993

No you are correct...if it were 25 - (-16) it would be 25 + 16 however here we have $\large \sqrt{(-5)^2 - 4(1)(4)}\rightarrow \sqrt{25 - (16)} = \sqrt{9}=3$

40. YanaSidlinskiy

Ok, I see where you're getting that from..

41. johnweldon1993

Good ^_^ so then yes we have $\large \frac{5 \pm 3}{2}$

42. YanaSidlinskiy

So the -4 is positive right? I'd read the 4 as a positive sign and the negative sign would be read to subtract right?

43. YanaSidlinskiy

I got 4,1

44. johnweldon1993

Well just take it part by part... $\large \sqrt{(-5)^2 - \color\red{(4(1)(4))}}$ focus on on the red first, dont even worry about that ''-" sign right now $\large \sqrt{25 - (16) }$

45. johnweldon1993

And yes 4 and 1 would be correct So now...we know these are the roots of your polynomial We write them as $\large (x - 4)(x-1) = 0$ And that is the factored form of it "why did it change to both being "minus"? Well because look at the equation...equal to 0 we want to be able to plug in either 4 or 1 into an equation and get 0....thus...we have that :)

46. YanaSidlinskiy

Ok, makes total sense lol.

47. johnweldon1993

does it really?

48. YanaSidlinskiy

Yeah I think haha. I may say something stupid right now cuz it's 1:31am..

49. johnweldon1993

Lol same here :P

50. YanaSidlinskiy

I'm a little cranky cuz I only got 3hrs of sleep last night. Haha. awesome!

51. johnweldon1993

Uh oh...get some sleep love :P

52. YanaSidlinskiy

Ik, but it's hard in cramming this homework and a final exam on campus tomorrow..

53. YanaSidlinskiy

If a polynomial does not factor out it'd be a prime right? cuz I'm asked to factor out 81x^2-1 But I get: 1(81x^2-1)

54. johnweldon1993

right, its just prime if nothing can be taken out

55. YanaSidlinskiy

okie. At least I got the last question right haha. There's more but I'll finish everything up tomorrow once I get up in like 3hrs... Goodnight! Sleep tight;)

56. johnweldon1993

Sleep tight hun ;)

57. YanaSidlinskiy

Hha, thanks lol ;) Anywho.. Audios!