YanaSidlinskiy
  • YanaSidlinskiy
I LOVE MATH!
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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chestercat
  • chestercat
I got my questions answered at brainly.com in under 10 minutes. Go to brainly.com now for free help!
johnweldon1993
  • johnweldon1993
Lol you love math? :P
YanaSidlinskiy
  • YanaSidlinskiy
I'm factoring out greatest common factors for this one:\[6x^3-8x^2+10x\]\[2x(3x^2-4x+5)\] That's what I got.. Is it right?
YanaSidlinskiy
  • YanaSidlinskiy
Yeah I definitely do. Can't you tell? lol;)

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johnweldon1993
  • johnweldon1993
Perfect! and oh of course ;P
YanaSidlinskiy
  • YanaSidlinskiy
Lol. yay haha. Factor by grouping: \[3x^2-6xy-4x+8y\]
YanaSidlinskiy
  • YanaSidlinskiy
I haven't got my answer yet but I'm working on it lol.
johnweldon1993
  • johnweldon1993
Tell me when you do :D
YanaSidlinskiy
  • YanaSidlinskiy
Ok, well for the first half I have 3x(x-2y)..... Blah...
johnweldon1993
  • johnweldon1993
Perfect....and the next half?
YanaSidlinskiy
  • YanaSidlinskiy
For the second half.. I have: 4(-x+2y)
YanaSidlinskiy
  • YanaSidlinskiy
Please tell me it's right lol.
YanaSidlinskiy
  • YanaSidlinskiy
WAIT.
YanaSidlinskiy
  • YanaSidlinskiy
LOL.
YanaSidlinskiy
  • YanaSidlinskiy
STOP>
YanaSidlinskiy
  • YanaSidlinskiy
I think I know what you're gonna say haha!
YanaSidlinskiy
  • YanaSidlinskiy
WAIT. PAUSE LOL>
johnweldon1993
  • johnweldon1993
Lol I'll wait ;P
YanaSidlinskiy
  • YanaSidlinskiy
It's the same thing hahaa;)
YanaSidlinskiy
  • YanaSidlinskiy
-4(x-2y)
johnweldon1993
  • johnweldon1993
There we go :P But what next? O.o
YanaSidlinskiy
  • YanaSidlinskiy
Idk you tell me haha
johnweldon1993
  • johnweldon1993
Lol so we have \[\large 3x(x - 2y) - 4(x - 2y)\] Since they both have a (x - 2y) in common...we factor that out...and write this as \[\large (3x - 4)(x - 2y)\]
YanaSidlinskiy
  • YanaSidlinskiy
Ohh yeah. Duhh I forgot lol. Thanks for the reminder.
johnweldon1993
  • johnweldon1993
Haha oh of course that's what I'm here for ;P
YanaSidlinskiy
  • YanaSidlinskiy
Hhaa, lol. I honestly can't explain how happy I am that you're on and you could help me LOL!
johnweldon1993
  • johnweldon1993
Well I had to cuz I love you remember <3 ;D lol No I like helping you cuz you dont bug me :P
YanaSidlinskiy
  • YanaSidlinskiy
\[x^2-5x+4\] So I'm supposed to be factoring this out... Haven't done it but I'll give it a shot lol. Ohh yeah hhaa. Duhh<3 Are you sure I don't? I feel like I am haha.
YanaSidlinskiy
  • YanaSidlinskiy
I'd set it to 0 right?
johnweldon1993
  • johnweldon1993
Lol nope you do all the work and I sit here and wait ;P And yes set it equal to 0
YanaSidlinskiy
  • YanaSidlinskiy
Hha, ok lol. Ok: So I have this so far: \[\frac{ -(-5)\pm \sqrt{(-5)^2-4(1)(4)} }{ 2(1) }\]
johnweldon1993
  • johnweldon1993
mmhmm....continue :)
YanaSidlinskiy
  • YanaSidlinskiy
I got prime. Is it right?
johnweldon1993
  • johnweldon1993
Huh? \[\large \frac{5 \pm \sqrt{9}}{2}\] is what I get
YanaSidlinskiy
  • YanaSidlinskiy
Well 4*-4 = -16 And -5*-5=25 and I added that and got 41...
johnweldon1993
  • johnweldon1993
25 + -16 would be subtraction :)
YanaSidlinskiy
  • YanaSidlinskiy
Well, I thought like if there's something like this: 25-(-16)... You would add...
YanaSidlinskiy
  • YanaSidlinskiy
OH WAIT. THAT'S FOR ADDITION right?
YanaSidlinskiy
  • YanaSidlinskiy
Or something idk...
johnweldon1993
  • johnweldon1993
No you are correct...if it were 25 - (-16) it would be 25 + 16 however here we have \[\large \sqrt{(-5)^2 - 4(1)(4)}\rightarrow \sqrt{25 - (16)} = \sqrt{9}=3\]
YanaSidlinskiy
  • YanaSidlinskiy
Ok, I see where you're getting that from..
johnweldon1993
  • johnweldon1993
Good ^_^ so then yes we have \[\large \frac{5 \pm 3}{2}\]
YanaSidlinskiy
  • YanaSidlinskiy
So the -4 is positive right? I'd read the 4 as a positive sign and the negative sign would be read to subtract right?
YanaSidlinskiy
  • YanaSidlinskiy
I got 4,1
johnweldon1993
  • johnweldon1993
Well just take it part by part... \[\large \sqrt{(-5)^2 - \color\red{(4(1)(4))}}\] focus on on the red first, dont even worry about that ''-" sign right now \[\large \sqrt{25 - (16) }\]
johnweldon1993
  • johnweldon1993
And yes 4 and 1 would be correct So now...we know these are the roots of your polynomial We write them as \[\large (x - 4)(x-1) = 0\] And that is the factored form of it "why did it change to both being "minus"? Well because look at the equation...equal to 0 we want to be able to plug in either 4 or 1 into an equation and get 0....thus...we have that :)
YanaSidlinskiy
  • YanaSidlinskiy
Ok, makes total sense lol.
johnweldon1993
  • johnweldon1993
does it really?
YanaSidlinskiy
  • YanaSidlinskiy
Yeah I think haha. I may say something stupid right now cuz it's 1:31am..
johnweldon1993
  • johnweldon1993
Lol same here :P
YanaSidlinskiy
  • YanaSidlinskiy
I'm a little cranky cuz I only got 3hrs of sleep last night. Haha. awesome!
johnweldon1993
  • johnweldon1993
Uh oh...get some sleep love :P
YanaSidlinskiy
  • YanaSidlinskiy
Ik, but it's hard in cramming this homework and a final exam on campus tomorrow..
YanaSidlinskiy
  • YanaSidlinskiy
If a polynomial does not factor out it'd be a prime right? cuz I'm asked to factor out 81x^2-1 But I get: 1(81x^2-1)
johnweldon1993
  • johnweldon1993
right, its just prime if nothing can be taken out
YanaSidlinskiy
  • YanaSidlinskiy
okie. At least I got the last question right haha. There's more but I'll finish everything up tomorrow once I get up in like 3hrs... Goodnight! Sleep tight;)
johnweldon1993
  • johnweldon1993
Sleep tight hun ;)
YanaSidlinskiy
  • YanaSidlinskiy
Hha, thanks lol ;) Anywho.. Audios!

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