## anonymous one year ago what is the length(magnitude) of the vector (6,-3)? A. 3sqrt2 B. sqrt2 C. 3 D. sqrt53

1. zzr0ck3r

length of vector $$(a,b)$$ is $$\sqrt{a^2+b^2}$$

2. mathstudent55

You need the hypotenuse of the right triangle. |dw:1438838359010:dw|

3. anonymous

would I be using the Pythagorean theorem?

4. rhr12

√(6^2 + (-3)^2) = √(36+9) = √(9*5) = 3√5

5. anonymous

Yes, Pythagoras' Theorem is the way to figure out the length of this vector.