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anonymous
 one year ago
HEEELPPPPP!!
anonymous
 one year ago
HEEELPPPPP!!

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anonymous
 one year ago
Best ResponseYou've already chosen the best response.0\[\frac{ 4x^29y^2 }{ 3x2y }\]

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0hmm.. zero and negative exponents.. just simplify

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0teach me how to get the answer :)

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Step one of simplifying is to use the negative power rule. The equation will be turned into \[(4×\frac{ 1 }{ x^2}−9y×\frac{ 1 }{ y^2 })(3x−2y)\] Simplify even further by multiplying 4 and 9 with the fractions. Then, once you solved everything on the left parenthesis, cross multiply with the parenthesis on the right.

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Do you still need help with simplifying?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0hmm. \[\frac{ 5x^2y^2+x^2y^2 }{ x^2y^2 } \times \frac{ 1 }{ 3x2y }\]

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Multiply \[(4×\frac{1}{x^2})\] and \[(−9y×\frac{1}{y^2})\]

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0= to 5x^2y^2+x^2y^2 over x^2y^2

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0then divide 3x2y .. ?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0\[\frac{ 4}{ 1} (\frac{ 1 }{ x^2 })\] \[\frac{ 9 }{ 1 } (\frac{ 1 }{ y^2 })\]

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0To multiply fractions, you multiply them across one another.

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Also, you don't divide 3x2y. The equation calls to multiply it to the equation in parenthesis on the left.

anonymous
 one year ago
Best ResponseYou've already chosen the best response.04x^29y^2+2 times 3x2y ?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0The (4x^2−9y^2) part is correct. That is the numerator of the left parenthesis. Now, find the denominator. Look back on the denominators of \[\frac{ 4}{ 1} (\frac{ 1 }{ x^2 })\] and \[\frac{ 9 }{ 1 } (\frac{ 1 }{ y^2 })\].

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Correct. That's the denominator of the equation. Now, plug it in with the numerator. The equation is now \[\frac{4{y}^{2}9{x}^{2}}{{x}^{2}{y}^{2}}\times 3x2y\]. Cross multiply it

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0\[\frac{4{y}^{2}9{x}^{2}}{{x}^{2}{y}^{2}}\times \frac{ 3x2y }{ 1 }\]

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0so the answer is \[\frac{ (3x+2y)(3x2y)^2 }{ x^2y^2 }\]

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Okay so you cross multiply \[\frac{4{y}^{2}9{x}^{2}}{{x}^{2}{y}^{2}}\times 3x2y\]. The numerator can be simplified even further by using the difference of squares. The difference of squares fits the form a^2  b^2. a = 2y and b = 3x. The equation rewritten will be \[\frac{{(2y)}^{2}{(3x)}^{2}}{{x}^{2}{y}^{2}}\times 3x2y\]. It can be simplified into \[\frac{(2y+3x)(2y3x)}{{x}^{2}{y}^{2}}\times 3x2y\] Also, further simplification can be \[\frac{3(2y+3x)(2y3x)}{x{y}^{2}}2y\] Moving the multiplication sign along with the squares.
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