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anonymous

  • one year ago

2t^2+5t+?=0 How can i get the 3rd term?

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  1. Astrophysics
    • one year ago
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    You can complete the square

  2. phi
    • one year ago
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    the third term could be anything (unless we have more info) if we assume this equation is in standard form, the third term would be a number (with no "t" variable) for example, it could be 0, 1, 2, or pi , etc

  3. phi
    • one year ago
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    if we know the expression is a "perfect square" then we would do as astro suggests.

  4. Astrophysics
    • one year ago
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    So if you have \[x^2+ax=0\] we can do the following \[x^2+\frac{ 2ax }{ 2 } + \left( \frac{ a }{ 2 } \right)^2-\left( \frac{ a }{ 2 } \right)^2=0\] (complete the square)

  5. anonymous
    • one year ago
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    your correct!

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