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Imtiaz7
 one year ago
Help Please...!!!
Imtiaz7
 one year ago
Help Please...!!!

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Imtiaz7
 one year ago
Best ResponseYou've already chosen the best response.0Convert following matrix into Reduced Echlon Form:

UsukiDoll
 one year ago
Best ResponseYou've already chosen the best response.3just reduce echelon form right?

UsukiDoll
 one year ago
Best ResponseYou've already chosen the best response.3so what we need is an upper triangular matrix which means that below the main diagonal we need all 0's we can achieve this by using row operations by swapping rows, multiplying a row by a scalar number, or add/subtract rows and replace the old row with the new result after that computation

UsukiDoll
 one year ago
Best ResponseYou've already chosen the best response.3keep in mind that we need a 1 always at the top left the 1 also has to go towards the right and the bottom... we also need a row of zeros

Imtiaz7
 one year ago
Best ResponseYou've already chosen the best response.0wait I've solve this, can you please tell me is this right?

UsukiDoll
 one year ago
Best ResponseYou've already chosen the best response.3dw:1438863440670:dw so the places I've circled is the main diagonal so we need to get rid of the 3 , 1, and 4 using row operations... yeah sure.

UsukiDoll
 one year ago
Best ResponseYou've already chosen the best response.3anyway... 3r1 + r2 > r2 r1+ r3  > r3

UsukiDoll
 one year ago
Best ResponseYou've already chosen the best response.3dw:1438863691395:dwdw:1438863716259:dw

UsukiDoll
 one year ago
Best ResponseYou've already chosen the best response.3dw:1438863747952:dw

UsukiDoll
 one year ago
Best ResponseYou've already chosen the best response.3hmmm gonna make life a bit easier by 1/2r3>r3

UsukiDoll
 one year ago
Best ResponseYou've already chosen the best response.3dw:1438863802231:dw

UsukiDoll
 one year ago
Best ResponseYou've already chosen the best response.3dw:1438863836507:dw

UsukiDoll
 one year ago
Best ResponseYou've already chosen the best response.31/10 r3  >r3 1/11 r2  > r2

UsukiDoll
 one year ago
Best ResponseYou've already chosen the best response.3dw:1438863882447:dw

UsukiDoll
 one year ago
Best ResponseYou've already chosen the best response.3do you have a matrix that looks like this? ^

UsukiDoll
 one year ago
Best ResponseYou've already chosen the best response.3how did you get 20/11 ?

Imtiaz7
 one year ago
Best ResponseYou've already chosen the best response.0by multiplying Row 2 by 2 and add it in row 3(2*1/11 + 2)

UsukiDoll
 one year ago
Best ResponseYou've already chosen the best response.3hmmm dealing with fractions that early is killer though

UsukiDoll
 one year ago
Best ResponseYou've already chosen the best response.3because what I've done to the third row was divide by 1/2 all over row 3 so I would have just 0 1 1

UsukiDoll
 one year ago
Best ResponseYou've already chosen the best response.3so when I had 0 11 1 0 1 1 I distributed the negative sign on row 2 and then multiply row 3 with 11 r2+11r^3 > r^3

UsukiDoll
 one year ago
Best ResponseYou've already chosen the best response.30 11 1 0 11 11 adding them together would make it 0 0 10 and then 1/10r3 >r3 to get rid of that 10 to have 0 0 1

Imtiaz7
 one year ago
Best ResponseYou've already chosen the best response.0but in last it becomes in reduced echlon form; isnt?

UsukiDoll
 one year ago
Best ResponseYou've already chosen the best response.3and then to have the 1 in the middle I had to divide the whole second row by 1/11

UsukiDoll
 one year ago
Best ResponseYou've already chosen the best response.3somehow our first rows are different but the second and third is the same..

Imtiaz7
 one year ago
Best ResponseYou've already chosen the best response.0does my answer is correct?

UsukiDoll
 one year ago
Best ResponseYou've already chosen the best response.3it should be as long as it followed the reduce echelon rules.. and it does. we do have an upper triangular matrix and our 1 is going down and shifted to the right

Imtiaz7
 one year ago
Best ResponseYou've already chosen the best response.0Yes! So our answers are different, but rules are same!

UsukiDoll
 one year ago
Best ResponseYou've already chosen the best response.3hmm I'm assuming that an extra step was taken to get rid of the 2 on the first row. unless we are required to get RREF form, that's not required. What's required is the numbers until the main diagonal go to 0.

UsukiDoll
 one year ago
Best ResponseYou've already chosen the best response.3check this one out... it also did something different but ended up with the same thing before taking RREF form oh that 1 in the third row got blocked out, but noticed how this calculator did something I disagree with, but still ends up following the rules?

UsukiDoll
 one year ago
Best ResponseYou've already chosen the best response.3that was done by a calculator bot... I really hated that 0 0 54/11 but by multiplying 11/54r3 > r3 0 0 1

Imtiaz7
 one year ago
Best ResponseYou've already chosen the best response.0@UsukiDoll the question is different there, that is there is 1 instead of 1 in first row

UsukiDoll
 one year ago
Best ResponseYou've already chosen the best response.3ugh a typo.. yeah this is way late at night... on my end.

UsukiDoll
 one year ago
Best ResponseYou've already chosen the best response.3still has that big fraction 20/11 on row 3 but 11/20r3  >r3 makes it 0 0 1

Imtiaz7
 one year ago
Best ResponseYou've already chosen the best response.0my answer is correct!!!

Imtiaz7
 one year ago
Best ResponseYou've already chosen the best response.0:) lol Thank you so much @UsukiDoll to help me..

UsukiDoll
 one year ago
Best ResponseYou've already chosen the best response.3XD you're welcome... these questions always come up very late at night, so typos are bound to happen... typed too fast XD

Imtiaz7
 one year ago
Best ResponseYou've already chosen the best response.0Its okay, when i post i dont run xD

UsukiDoll
 one year ago
Best ResponseYou've already chosen the best response.3yay I got it right too XD dw:1438865533703:dw row operation #5 on the correct image has the same matrix I had... only in fewer steps.

UsukiDoll
 one year ago
Best ResponseYou've already chosen the best response.3but as long as the rules aren't broken for row echelon form, then everything will be fine ^_^

Imtiaz7
 one year ago
Best ResponseYou've already chosen the best response.0Yup @UsukiDoll rules are for obey uhm i think so lol

Imtiaz7
 one year ago
Best ResponseYou've already chosen the best response.0There is still a confusion uhm the answer you showed me are correct one but in my answer in fist row there is 9/11, still is it right?

UsukiDoll
 one year ago
Best ResponseYou've already chosen the best response.3you mean for this right http://assets.openstudy.com/updates/attachments/55c34eede4b06d80932e63a6imtiaz7143886410735620150806_172006.jpg ?

UsukiDoll
 one year ago
Best ResponseYou've already chosen the best response.3as long as you have an upper triangular matrix which means all 0's below the main diagonal and have a 1 on the top left that goes to the bottom and right... I don't see a problem.

Imtiaz7
 one year ago
Best ResponseYou've already chosen the best response.0Once again thanks a lot :)

UsukiDoll
 one year ago
Best ResponseYou've already chosen the best response.3we could RREF that last matrix with that 9/11 if you want

UsukiDoll
 one year ago
Best ResponseYou've already chosen the best response.3to show that we can get an identity matrix out of some more row operations..

UsukiDoll
 one year ago
Best ResponseYou've already chosen the best response.3dw:1438866425233:dw this was the matrix you had in REF form right?

UsukiDoll
 one year ago
Best ResponseYou've already chosen the best response.3I would use row 3 to get rid of the remaining numbers above the main diagonal, but I hate dealing with fractions so 11r2  >r2 11r1 > r1

UsukiDoll
 one year ago
Best ResponseYou've already chosen the best response.3dw:1438866522476:dw

UsukiDoll
 one year ago
Best ResponseYou've already chosen the best response.3r3+r2  > r2 9r3 + r1  > r1

UsukiDoll
 one year ago
Best ResponseYou've already chosen the best response.3dw:1438866568376:dwdw:1438866589363:dw

Imtiaz7
 one year ago
Best ResponseYou've already chosen the best response.0@UsukiDoll can i give you another medal bc your math is too good

UsukiDoll
 one year ago
Best ResponseYou've already chosen the best response.31/11r2  >r2 1/11 r1 > r1... I wish we can give more than 1 medal XD

UsukiDoll
 one year ago
Best ResponseYou've already chosen the best response.3dw:1438866634762:dw aha identity matrix! so we got RREF XD

UsukiDoll
 one year ago
Best ResponseYou've already chosen the best response.3which means your row operations from earlier were correct... otherwise we wouldn't get RREF
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