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muscrat123

  • one year ago

@heretohelpalways

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  1. anonymous
    • one year ago
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    yes?

  2. muscrat123
    • one year ago
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    Maggie has 7 tiles with pictures of plants and 2 tiles with pictures of animals. Maggie keeps all the tiles on a mat with the pictures hidden and mixes them up. She then turns one tile face up and finds the picture of a plant on it. She removes this tile from the mat and turns over another tile without looking. What is the probability that the second tile that Maggie turns over has a plant on it? 22.2% 28.6% 65.0% 75.0% i think it may be A

  3. anonymous
    • one year ago
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    the new probability would be 6/8

  4. muscrat123
    • one year ago
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    so D?

  5. anonymous
    • one year ago
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    which is equal to....

  6. anonymous
    • one year ago
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    yup D

  7. muscrat123
    • one year ago
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    Ben has a 40% chance of being selected as the president of the school sports club and a 70% chance of being elected editor of the school magazine. What is the probability that Ben will be selected as the president of the sports club and will also be elected editor of the school magazine? 0.3% 1.1% 14% 28%

  8. muscrat123
    • one year ago
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    i dont know how to solve problems like this

  9. anonymous
    • one year ago
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    do 4 over 10 * 7 over 10

  10. anonymous
    • one year ago
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    \[\frac{ 4 }{ 10 }*\frac{ 7 }{ 10 }\]

  11. anonymous
    • one year ago
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    28/100

  12. muscrat123
    • one year ago
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    28%

  13. anonymous
    • one year ago
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    yup

  14. muscrat123
    • one year ago
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    Max tossed a fair coin 3 times. What is the probability of getting heads in the first two trials and tails in the last trial? 4 over 8 3 over 8 2 over 8 1 over 8

  15. anonymous
    • one year ago
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    do \[\frac{ 1 }{ 2 }*\frac{ 1 }{ 2 }*\frac{ 1 }{ 2 }\]

  16. anonymous
    • one year ago
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    I think

  17. anonymous
    • one year ago
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    I am really not sure about this one

  18. anonymous
    • one year ago
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    1/8

  19. muscrat123
    • one year ago
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    but 13% isnt an option

  20. anonymous
    • one year ago
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    1/8 is an option...

  21. muscrat123
    • one year ago
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    oh we are talking about the most recent question. i thought we were talking about the plant question

  22. anonymous
    • one year ago
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    |dw:1438870916332:dw|

  23. muscrat123
    • one year ago
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    At a game booth, a student gets a box of candy as the prize for winning a game. The boxes come in four colors: white, red, green, and blue. There are 10 boxes of each color. All the boxes are equally likely to be given away as prizes. Which expression shows the probability of the first winner receiving a white box and the second winner also receiving a box of the same color? 10 over 40 multiplied by 9 over 39 10 over 40 multiplied by 10 over 39 10 over 40 plus 9 over 39 10 over 40 plus 10 over 39

  24. anonymous
    • one year ago
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    you must NOT add these fractions, so that should eliminate 2 answer

  25. anonymous
    • one year ago
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    and a white box was taken out leaving the probability of a white box to be chosen 9/39

  26. anonymous
    • one year ago
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    so it would be A

  27. anonymous
    • one year ago
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    anymore questions?

  28. muscrat123
    • one year ago
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    sorry it took a while to respond - had to do an interview for flvs A box has 5 beads of the same size, but all are different colors. Tina draws a bead randomly from the box, notes its color, and then puts the bead back in the box. She repeats this 3 times. What is the probability that Tina would pick a red bead on the first draw, then a green bead, and finally a red bead again? 1 over 625 1 over 180 1 over 150 1 over 125 @heretohelpalways

  29. anonymous
    • one year ago
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    that's okay

  30. anonymous
    • one year ago
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    \frac{ 1 }{ 5 }*\frac{ 1 }{ 5 }*\frac{ 1 }{ 5 }

  31. anonymous
    • one year ago
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    do 1/5*1/5*1/5

  32. anonymous
    • one year ago
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    to get 1/125

  33. anonymous
    • one year ago
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    was the interview a DBA?

  34. muscrat123
    • one year ago
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    b4 the interview yes

  35. anonymous
    • one year ago
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    lol

  36. muscrat123
    • one year ago
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    i had to do an actual interview though

  37. muscrat123
    • one year ago
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    could u help with some more?

  38. anonymous
    • one year ago
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    sure

  39. muscrat123
    • one year ago
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    The following table shows the data collected from a random sample of 100 middle school students on the number of hours they play outdoor games every week:Weekly Duration of Outdoor Games Time (in hours) 0–2 3–5 6–8 9–11 Number of Students 30 62 8 0 There are 1,200 students in the school. Based on the sample proportion, how many students in the school would be expected to play outdoor games for at least three hours every week? 744 840 960 1,104

  40. anonymous
    • one year ago
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    can you make the table a bit cleaner?

  41. anonymous
    • one year ago
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    do 62+8+0

  42. anonymous
    • one year ago
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    to get 70%

  43. anonymous
    • one year ago
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    find 70% of 1,200

  44. anonymous
    • one year ago
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    to get the answer: 840

  45. muscrat123
    • one year ago
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    so the final answer is 840?

  46. anonymous
    • one year ago
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    yup

  47. muscrat123
    • one year ago
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    Jack wants to know how many families in his small neighborhood of 60 homes would help organize a neighborhood fund-raising party. He put all the addresses in a bag and drew a random sample of 30 addresses. He then asked those families if they would help organize the fund-raising party. He found that 12% of the families would help organize the party. He claims that 12% of the neighborhood families would be expected to help organize the party. Is this a valid inference? No, this is not a valid inference because he asked only 30 families No, this is not a valid inference because he did not take a random sample of the neighborhood Yes, this is a valid inference because he took a random sample of the neighborhood Yes, this is a valid inference because the 30 families speak for the whole neighborhood

  48. anonymous
    • one year ago
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    it is valid since he took a random sample

  49. muscrat123
    • one year ago
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    The price of some jewelry sets in a store are shown below: Store Price A $110,000 B $100,000 C $1,110,000 D $130,000 E $120,000 Based on the data, should the mean or the median be used to make an inference about the price of the jewelry sets in the store? Mean, because it is in the center of the data Median, because it is in the center of the data Median, because there is an outlier that affects the mean Mean, because there are no outliers that affect the mean @heretohelpalways

  50. anonymous
    • one year ago
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    median, since outliers don't affect medians so C

  51. muscrat123
    • one year ago
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    Noah wants to predict who will be selected as the sixth-grade treasurer for student council. Which of the following groups should Noah survey to make his prediction? The first 100 students from an alphabetical list of the entire school The first 100 students from an alphabetical list of sixth graders One hundred random students from the entire school One hundred random students from the sixth grade D correct @heretohelpalways ?

  52. muscrat123
    • one year ago
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    and also: Four students did a survey to find the pizza topping sixth-grade students prefer. The table below shows the method each student used to conduct the survey: Student Method Troy Asked 100 students at random from his seventh-grade class what their favorite pizza topping is Dacia Asked 100 eighth-grade students at random what their favorite pizza topping is Julia Asked 100 sixth-grade students at random what their favorite pizza topping is Tanner Asked 100 third-grade students at random what their favorite pizza topping is Which student's survey is most likely not biased? Troy Dacia Julia Tanner

  53. anonymous
    • one year ago
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    D is correcct

  54. anonymous
    • one year ago
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    and JUlia is not biased because she is the only one who asked sixth graders

  55. anonymous
    • one year ago
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    oops Julia

  56. muscrat123
    • one year ago
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    The following table shows the data collected from a random sample of 100 middle school students on the number of hours they play indoor games every week: Weekly Duration of Indoor Games Time (in hours) 0–3 4–7 8–11 12–15 Number of Students 4 42 52 2 There are 1,300 students in the school. Based on the sample proportion, how many students in the school would be expected to play indoor games for at least four hours every week? 546 598 702 1,248 \ @heretohelpalways

  57. anonymous
    • one year ago
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    ooops

  58. anonymous
    • one year ago
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    96% of 1,300

  59. anonymous
    • one year ago
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    1248

  60. muscrat123
    • one year ago
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    The dot plot below shows the amount of time two random groups of students took to brush their teeth: Based on visual inspection of the dot plots, which of the following groups, if any, shows a greater average time required to brush their teeth? Group R Group S Both groups show about the same average time. No conclusion about average time can be made from the data. @heretohelpalways

  61. muscrat123
    • one year ago
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    group s?

  62. anonymous
    • one year ago
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    I am not really sure...

  63. muscrat123
    • one year ago
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    The price of some jewelry sets in a store are shown below: Store Price A $110,000 B $100,000 C $1,110,000 D $130,000 E $120,000 Based on the data, should the mean or the median be used to make an inference about the price of the jewelry sets in the store? Mean, because it is in the center of the data Median, because it is in the center of the data Median, because there is an outlier that affects the mean Mean, because there are no outliers that affect the mean C?

  64. anonymous
    • one year ago
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    try calculating the mean

  65. anonymous
    • one year ago
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    of each

  66. muscrat123
    • one year ago
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    The price of some jewelry sets in a store are shown below: Store Price A $110,000 B $100,000 C $1,110,000 D $130,000 E $120,000 Based on the data, should the mean or the median be used to make an inference about the price of the jewelry sets in the store? Mean, because it is in the center of the data Median, because it is in the center of the data Median, because there is an outlier that affects the mean Mean, because there are no outliers that affect the mean C? and document.rtf is a different question

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