Two different plants grow each year at different rates, which are represented by the functions f(x) = 4x and g(x) = 5x + 2. What is the first year the f(x) height is greater than the g(x) height?
A. Year 0
B.Year 1
C.Year 2
D.Year 3
Can i get some help plz

- anonymous

- Stacey Warren - Expert brainly.com

Hey! We 've verified this expert answer for you, click below to unlock the details :)

- schrodinger

I got my questions answered at brainly.com in under 10 minutes. Go to brainly.com now for free help!

- anonymous

@ali2x2

- anonymous

@Michele_Laino can u help me plz

- Michele_Laino

you have to substitute x=0, 1,2,3 then you have to compare the values f(x) and g(x) for each year.
For example, if x=0, then we have:
f(0) = 4*0 =0, and g(0)= 5*0+2=2, so f(0) < g(0)
now, please do the same for other values of x

Looking for something else?

Not the answer you are looking for? Search for more explanations.

## More answers

- anonymous

so pu 4 in for f in the problem and 5 in for g

- anonymous

u there

- Michele_Laino

yes!

- Michele_Laino

question:
are f(x) and g(x) heights or rates?

- anonymous

rates

- Michele_Laino

so, are you familiar with differential calculus?

- anonymous

no i am not ?

- Michele_Laino

if f(x) is a rate, then the corresponding height h, is given solving this differential equation:
\[\Large \frac{{dh}}{{dx}} = 4x\]

- anonymous

ok i am trying to understand what is going on but for my first answer i put B. am i right

- Michele_Laino

I'm pondering...

- anonymous

okay

- Michele_Laino

my reasoning is:
height h1 for f(x) is:
\[\Large {h_1}\left( x \right) = 2{x^2}\]
whereas height h2 for g(x) is:
\[\Large {h_2}\left( x \right) = \frac{{5{x^2}}}{2} + 2x\]
and we have h2>h1, if x>0, whereas h2=h1 if x=0

- Michele_Laino

please wait I ask to another helper

- anonymous

so A

- Michele_Laino

@Astrophysics please help

- Michele_Laino

@vera_ewing @nincompoop please help

- anonymous

so what i need to do

- Astrophysics

This doesn't really make sense, are the functions
\[f(x)=4x~~and~~g(x) = 5x+2~~~~or~~~~f(x)=4^x~~~~and~~~g(x) = 5x+2\]

- anonymous

Two different plants grow each year at different rates, which are represented by the functions f(x) = 4x and g(x) = 5x + 2. What is the first year the f(x) height is greater than the g(x) height?
this is the problem

- Astrophysics

What are the functions...from what i showed you

- Astrophysics

is it to the power of x or just times x...

- anonymous

just times

- Astrophysics

So it's \[f(x) = 4x\] and \[g(x) = 5x+2\]

- anonymous

i am so confused tho

- Astrophysics

Can you please take an image of your question and post it

- anonymous

i dont know how to do thatfrom computer

- anonymous

Two different plants grow each year at different rates, which are represented by the functions f(x) = 4x and g(x) = 5x + 2. What is the first year the f(x) height is greater than the g(x) height?
Year 0
Year 1
Year 2
Year 3

- Astrophysics

Ok all I am asking you is, what are the functions they gave you in the problem f(x), if it's to the power of x or is just 4x...

- Astrophysics

and same for g(x)

- Astrophysics

|dw:1438873919146:dw|

- anonymous

Two different plants grow each year at different rates, which are represented by the functions f(x) = 4x and g(x) = 5x + 2 What is the first year the f(x) height is greater than the g(x) height?
Year 0
Year 1
Year 2
Year 3

- Astrophysics

cmon dude lol

- anonymous

lol tbh i dont know

- Astrophysics

Im asking you about the problem

- Astrophysics

not how to do it

- anonymous

lol o....

- Astrophysics

Two different plants grow each year at different rates, which are represented by the functions `f(x) = 4x and g(x) = 5x + 2` What is the first year the f(x) height is greater than the g(x) height?

- Astrophysics

Are those to the power of x or just being multiplied by x

- anonymous

being multiplied

- Astrophysics

So it's exactly \[f(x) = 4x~~~~~g(x) = 5x+2\] like that right?

- anonymous

yes that right

- Astrophysics

Ok well...then you can make a graph check this out |dw:1438874246367:dw| blue is g(x) and green is f(x)

- anonymous

what am i looking for in the picture

- Astrophysics

This doesn't make sense

- Astrophysics

This shows g(x) > f(x) always

- anonymous

ok so make a graph

- Astrophysics

Can you please take a screenshot of your problem

- anonymous

how can u screen shot from computer

- anonymous

did u get it

- Astrophysics

not yet

- Astrophysics

Ok I got it and it was to the power of x, I KNEW IT!! haha|dw:1438875745626:dw|

- anonymous

lol okay

- Astrophysics

Ok so now we can put in values as Michele did above, to see so let x = 0 \[f(0) = 4^0 = 1\]
\[g(0) = 5(0)+2=2\]
So its not year 0

- anonymous

its 2

- anonymous

C.

- Astrophysics

\[f(1) = 4^1=4\]
\[g(1) = 5(1)+2=7\] year 1
\[f(2) = 4^2 = 16~~~~g(2) = 5(2)+2 = 12\]

- Astrophysics

Yup year 2 lol

- Astrophysics

Bleh, that took so long xD, I knew something was fishy

- anonymous

lol okay thx for your time

- anonymous

Which of the following exponential functions goes through the points (1, 6) and (2, 12)?
f(x) = 3(2)x
f(x) = 2(3)x
f(x) = 3(2)−x
f(x) = 2(3)−x

- anonymous

help me with this @Astrophysics

- Astrophysics

Lol no problem

- Astrophysics

Please open a new question

- anonymous

lol okay

Looking for something else?

Not the answer you are looking for? Search for more explanations.