A 4,000 mL solution of AgNO3 contains 17.00 g of solute in water. Calculate the molarity (molar concentration) of the solution.

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A 4,000 mL solution of AgNO3 contains 17.00 g of solute in water. Calculate the molarity (molar concentration) of the solution.

Chemistry
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c=(m/v)x(1/MW) Where c is the molar concentration or molarity, your unknown m is the mass of solute in grams, so the 17.00g v is the volume in litres, so you would have to convert it to L from mL MW is the molecular weight so you have to find the molar mass of AgNO3
molarity is defined as moles per litre. Meaning, \(\large \sf \color{red}{\frac{mol}{L}}\) Most of what you're doing in general chemistry is following units. If you know the units, you can get to where you need to get.
Keeping in mind that you need to eliminate grams of solute and convert to moles using molar mass (which is in units of \(\sf \color{red}{\frac{g}{mol}}\). Refer to the periodic table here for this, if you don't have one, here's a nice one you can use: http://www.ptable.com/

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