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anonymous

  • one year ago

Please help me (NO DIRECT ANSWERS) :) I WILL MEDAL/FAN

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  1. anonymous
    • one year ago
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    Belinda wants to invest $1000. The table below shows the value of her investment under two different options for three different years: Number of years 1 2 3 Option 1 (amount in dollars) 1300 1690 2197 Option 2 (amount in dollars) 1300 1600 1900 Part A: What type of function, linear or exponential, can be used to describe the value of the investment after a fixed number of years using option 1 and option 2? Explain your answer. (2 points) Part B: Write one function for each option to describe the value of the investment f(n), in dollars, after n years. (4 points) Part C: Belinda wants to invest in an option that would help to increase her investment value by the greatest amount in 20 years. Will there be any significant difference in the value of Belinda's investment after 20 years if she uses option 2 over option 1? Explain your answer, and show the investment value after 20 years for each option. (4 points)

  2. anonymous
    • one year ago
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    @saseal last one :)

  3. anonymous
    • one year ago
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    lemme study this wall of text

  4. anonymous
    • one year ago
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    okay dookie

  5. anonymous
    • one year ago
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    Part A is asking about linear and exponential function, you know the different between em right?

  6. anonymous
    • one year ago
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    Yes ma'am/sir

  7. anonymous
    • one year ago
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    im doge xD

  8. anonymous
    • one year ago
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    so a guyyy??? Like I am really slow btw

  9. anonymous
    • one year ago
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    you can prolly guess which one is a linear function and exponential just by looking

  10. anonymous
    • one year ago
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    maybeee???

  11. anonymous
    • one year ago
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    i can but i dont know about you

  12. anonymous
    • one year ago
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    option one is exponential and option 2 is linear

  13. anonymous
    • one year ago
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    possibly OS makes me feel really stupid

  14. anonymous
    • one year ago
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    you are correct

  15. anonymous
    • one year ago
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    but for the explanation part

  16. anonymous
    • one year ago
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    option two is linear because it increases by a fixed amount?

  17. anonymous
    • one year ago
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    its describing the difference between this 2 functions. btw “Everybody is a genius. But if you judge a fish by its ability to climb a tree, it will live its whole life believing that it is stupid.” - Albert Einstein

  18. anonymous
    • one year ago
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    yea

  19. anonymous
    • one year ago
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    okay so "option two is linear because it increases by a fixed amount"

  20. anonymous
    • one year ago
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    yea

  21. anonymous
    • one year ago
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    I am not sure about option one though

  22. anonymous
    • one year ago
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    when you did the last question, exponential increase by what factor?

  23. anonymous
    • one year ago
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    the f(x) of your last question

  24. anonymous
    • one year ago
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    3%

  25. anonymous
    • one year ago
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    its a power right?

  26. anonymous
    • one year ago
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    0.69*1.03^x

  27. anonymous
    • one year ago
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    its a compounding 3%

  28. anonymous
    • one year ago
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    yes...but this question doesn't have an equation.

  29. anonymous
    • one year ago
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    yea that f(x) is an exponential equation just like option 1

  30. anonymous
    • one year ago
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    whatt?

  31. anonymous
    • one year ago
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    they behave the same way

  32. anonymous
    • one year ago
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    like this on the graph|dw:1438877568681:dw|

  33. anonymous
    • one year ago
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    they have different flavors but they increase to a very steep gradient in the end

  34. anonymous
    • one year ago
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    increase or decrease depends on the function

  35. anonymous
    • one year ago
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    they dont behave like a linear function which looks like this on the graph|dw:1438877675414:dw|

  36. anonymous
    • one year ago
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    okayy sooo...

  37. anonymous
    • one year ago
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    option b has a quantity growth proportional to its current value

  38. anonymous
    • one year ago
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    thats what makes it exponential

  39. anonymous
    • one year ago
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    option a you mean?

  40. anonymous
    • one year ago
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    yea

  41. anonymous
    • one year ago
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    Part B now?

  42. anonymous
    • one year ago
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    Part B: Write one function for each option to describe the value of the investment f(n), in dollars, after n years.

  43. anonymous
    • one year ago
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    option 2 first: its y=mx+b option 1: you want me to hand you compound interest formula?

  44. anonymous
    • one year ago
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    what? I know y=mx+b. But how does that apply to this? and yes please

  45. anonymous
    • one year ago
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    y=mx+b b is your y-intercept where its year 0 which is 1000. now from there what is the rate of change of the $$$ per year? that will be your m

  46. anonymous
    • one year ago
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    okay. Help?

  47. anonymous
    • one year ago
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    compound interest formula\[A=P(1+\frac{ r }{ 100 })^n\]

  48. anonymous
    • one year ago
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    A=amount accumulated P=principal amount r=interest rate n=years

  49. anonymous
    • one year ago
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    yes I know that we were taught this: f(x)=p(1+r)^x where r was the rate in decimal form, p was principle and x was x

  50. anonymous
    • one year ago
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    y=mx+1000 1000 is your principal

  51. anonymous
    • one year ago
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    okay

  52. anonymous
    • one year ago
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    now lets find your m with 2 points

  53. anonymous
    • one year ago
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    ok, what about 1 and 0

  54. anonymous
    • one year ago
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    0 is year 0, whats your $ at year 0?

  55. anonymous
    • one year ago
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    for option B?its 1000

  56. anonymous
    • one year ago
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    now year 1 of option b?

  57. anonymous
    • one year ago
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    1300

  58. anonymous
    • one year ago
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    now you have your 2 points (0,1000) and (1,1300)

  59. anonymous
    • one year ago
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    you can find your slope from here

  60. anonymous
    • one year ago
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    \[m=\frac{ y_2-y_1 }{ x_2-x_1 }\]

  61. anonymous
    • one year ago
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    1300-1000/1-0

  62. anonymous
    • one year ago
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    yes

  63. anonymous
    • one year ago
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    300/1 or 300

  64. anonymous
    • one year ago
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    nvm ill show you the simple interest formula so you dont get confused

  65. anonymous
    • one year ago
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    okay?

  66. anonymous
    • one year ago
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    \[I=P \times R \times T\]

  67. anonymous
    • one year ago
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    OKOKOKOk wut?

  68. anonymous
    • one year ago
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    interest rate is \[\frac{ 1300-1000 }{ 1000 } \times 100\] I = interest created P = principal R = interest rate T = time

  69. anonymous
    • one year ago
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    300/1000*100=30

  70. anonymous
    • one year ago
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    yup

  71. anonymous
    • one year ago
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    we are still on part B?

  72. anonymous
    • one year ago
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    right?

  73. anonymous
    • one year ago
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    yes

  74. anonymous
    • one year ago
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    okay. What was that the answer to? 30

  75. anonymous
    • one year ago
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    now we are support to create function

  76. anonymous
    • one year ago
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    okay so f(x)=300

  77. anonymous
    • one year ago
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    lol

  78. anonymous
    • one year ago
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    we piece the part of the simple interest formula + principal to get the answer

  79. anonymous
    • one year ago
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    like this f(x)=x+(P*R*T)

  80. anonymous
    • one year ago
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    ok

  81. anonymous
    • one year ago
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    oops its f(x)=1000+(1000*R*x)

  82. anonymous
    • one year ago
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    since x is time which is the only thing that changes

  83. anonymous
    • one year ago
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    test this function see if it works

  84. anonymous
    • one year ago
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    So the answer to part B for Option 2<< or 1 am not sure is f(x)=1000+(1000*R*x)

  85. anonymous
    • one year ago
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    lets see...\[f(1)=1000+(1000*0.3*1)=1300\]\[f(2)=1000+(1000*0.3*2)=1600\]

  86. anonymous
    • one year ago
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    thats good for your part b option 2

  87. anonymous
    • one year ago
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    for option 1 its the compound interest formula, you can find your interest rate like this\[\frac{ 1300-1000 }{ 1000 } \times 100\]

  88. anonymous
    • one year ago
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    \[f(x)=1000(1.3)^x\]

  89. anonymous
    • one year ago
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    "f(1)=1000+(1000∗0.3∗1)=1300 f(2)=1000+(1000∗0.3∗2)=1600" for option b?

  90. anonymous
    • one year ago
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    nah its \[f(x)=1000+(1000*0.3*x)\]you can simplify it further if you like to

  91. anonymous
    • one year ago
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    well its an essay q, I do not know what its asking for, but I gave the specific question

  92. anonymous
    • one year ago
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    they say write function, you cant write an essay on that

  93. anonymous
    • one year ago
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    not literal essay, I mean its not graded by the computer, its by the teacher, so I am not sure what specifically the answer is, since ther are no multiple choice.

  94. anonymous
    • one year ago
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    they are asking you to craft a function that whenever you put in a year, it will churn out something that tells you the $ you get when you put your $ in for that amount of year

  95. anonymous
    • one year ago
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    okay moving on. Option A?

  96. anonymous
    • one year ago
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    scroll up abit

  97. anonymous
    • one year ago
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    okay. Part C?

  98. anonymous
    • one year ago
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    Belinda wants to invest in an option that would help to increase her investment value by the greatest amount in 20 years. Will there be any significant difference in the value of Belinda's investment after 20 years if she uses option 2 over option 1? Explain your answer, and show the investment value after 20 years for each option.

  99. anonymous
    • one year ago
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    now plug in 20 into both functions and see the difference

  100. anonymous
    • one year ago
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    where is the n in the function for option 1? f(x)=1000(1.3)x WOAH WOAH WOAH JUST TO GET THIS ALL CLEAR, OPTION 2: f(x)=1000+(1000*0.3*n) OPTION 1:f(x)=1000(1.3)x

  101. anonymous
    • one year ago
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    yea

  102. anonymous
    • one year ago
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    Option 1:\[f(x)=1000(1.3)^x\]Option 2:\[f(x)=1000+(1000*0.3*x)\]

  103. anonymous
    • one year ago
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    OKAY so next, we fill in 20 f(x)=1000*190.049637749

  104. anonymous
    • one year ago
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    190049.637749

  105. anonymous
    • one year ago
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    yea no problem

  106. anonymous
    • one year ago
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    now compare that to option 2

  107. anonymous
    • one year ago
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    f(x)=1000+(1000∗0.3∗20) 7000 and

  108. anonymous
    • one year ago
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    190049.637749 and 7000

  109. anonymous
    • one year ago
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    whats 190049.637749-7000

  110. anonymous
    • one year ago
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    183049.638

  111. anonymous
    • one year ago
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    now you got your numbers go explain it

  112. anonymous
    • one year ago
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    do you think 180349.638 is a signifcant difference?

  113. anonymous
    • one year ago
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    yeahhh

  114. anonymous
    • one year ago
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    thanks for the help :)

  115. anonymous
    • one year ago
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    yw

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