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lemme study this wall of text

okay dookie

Part A is asking about linear and exponential function, you know the different between em right?

Yes ma'am/sir

im doge xD

so a guyyy??? Like I am really slow btw

you can prolly guess which one is a linear function and exponential just by looking

maybeee???

i can but i dont know about you

option one is exponential and option 2 is linear

possibly
OS makes me feel really stupid

you are correct

but for the explanation part

option two is linear because it increases by a fixed amount?

yea

okay so "option two is linear because it increases by a fixed amount"

yea

I am not sure about option one though

when you did the last question, exponential increase by what factor?

the f(x) of your last question

3%

its a power right?

0.69*1.03^x

its a compounding 3%

yes...but this question doesn't have an equation.

yea that f(x) is an exponential equation just like option 1

whatt?

they behave the same way

like this on the graph|dw:1438877568681:dw|

they have different flavors but they increase to a very steep gradient in the end

increase or decrease depends on the function

they dont behave like a linear function which looks like this on the graph|dw:1438877675414:dw|

okayy sooo...

option b has a quantity growth proportional to its current value

thats what makes it exponential

option a you mean?

yea

Part B now?

option 2 first: its y=mx+b
option 1: you want me to hand you compound interest formula?

what? I know y=mx+b. But how does that apply to this? and yes please

okay. Help?

compound interest formula\[A=P(1+\frac{ r }{ 100 })^n\]

A=amount accumulated
P=principal amount
r=interest rate
n=years

y=mx+1000
1000 is your principal

okay

now lets find your m with 2 points

ok, what about 1 and 0

0 is year 0, whats your $ at year 0?

for option B?its 1000

now year 1 of option b?

1300

now you have your 2 points (0,1000) and (1,1300)

you can find your slope from here

\[m=\frac{ y_2-y_1 }{ x_2-x_1 }\]

1300-1000/1-0

yes

300/1 or 300

nvm ill show you the simple interest formula so you dont get confused

okay?

\[I=P \times R \times T\]

OKOKOKOk wut?

300/1000*100=30

yup

we are still on part B?

right?

yes

okay. What was that the answer to? 30

now we are support to create function

okay so f(x)=300

lol

we piece the part of the simple interest formula + principal to get the answer

like this f(x)=x+(P*R*T)

ok

oops its f(x)=1000+(1000*R*x)

since x is time which is the only thing that changes

test this function see if it works

So the answer to part B for Option 2<< or 1 am not sure is f(x)=1000+(1000*R*x)

lets see...\[f(1)=1000+(1000*0.3*1)=1300\]\[f(2)=1000+(1000*0.3*2)=1600\]

thats good for your part b option 2

\[f(x)=1000(1.3)^x\]

"f(1)=1000+(1000∗0.3∗1)=1300
f(2)=1000+(1000∗0.3∗2)=1600" for option b?

nah its \[f(x)=1000+(1000*0.3*x)\]you can simplify it further if you like to

well its an essay q, I do not know what its asking for, but I gave the specific question

they say write function, you cant write an essay on that

okay moving on. Option A?

scroll up abit

okay. Part C?

now plug in 20 into both functions and see the difference

yea

Option 1:\[f(x)=1000(1.3)^x\]Option 2:\[f(x)=1000+(1000*0.3*x)\]

OKAY so next, we fill in 20
f(x)=1000*190.049637749

yea no problem

now compare that to option 2

f(x)=1000+(1000∗0.3∗20)
7000 and

190049.637749 and 7000

whats 190049.637749-7000

183049.638

now you got your numbers go explain it

do you think 180349.638 is a signifcant difference?

yeahhh

thanks for the help :)

yw