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cookie_monster

  • one year ago

HELP PLEASE!!! LITERAL EQUATIONS!!

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  1. cookie_monster
    • one year ago
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    The area of this figure can be found by the formula A = (wh) + 0.5(bh). If Marcie wants the total area to be larger than a specified value, she can use the formula A > (wh)+ 0.5(bh). Rewrite this formula to solve for b. Show all steps in your work.

  2. cookie_monster
    • one year ago
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    A > (wh)+0.5(bh) A(wh) > 0.5(bh) A(wh) * 2 > (bh) A(wh) * 2/h > (b) This the answer I got, but I have a feeling it's not correct.

  3. Nnesha
    • one year ago
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    wh is adding with .5(bh) so to cancel out wh from right you need to do opposite of addition

  4. Nnesha
    • one year ago
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    multiplication <----opposite ----> division

  5. Nnesha
    • one year ago
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    ??

  6. cookie_monster
    • one year ago
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    Ok, so A - (wh) > 0.5(bh)

  7. cookie_monster
    • one year ago
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    What I really need to know is how I deal with the 0.5. That's what's getting and it's on multiple problems

  8. cookie_monster
    • one year ago
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    @Nnesha You there?

  9. Nnesha
    • one year ago
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    oops oh yea so that's right now multiply both sides by 2 remember .5 =1/2 so you can change it to fraction \[\huge\rm A-wh>\frac{ bh }{ 2 }\]

  10. cookie_monster
    • one year ago
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    So the answer would be \[b < A - (wh) * 2 \div h\]

  11. Nnesha
    • one year ago
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    multiply left side by 2 so 2(a-wh)

  12. Nnesha
    • one year ago
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    \[\huge\rm \frac{ 2(A-wh) }{ h }>b\] multiply whole thingy not just wh

  13. Nnesha
    • one year ago
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    now distribute parentheses by 2

  14. cookie_monster
    • one year ago
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    Ah ok. Thank you so much!! I understand now.

  15. Nnesha
    • one year ago
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    my pleasure

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