The area of this figure can be found by the formula A = (wh) + 0.5(bh). If Marcie wants the total area to be larger than a specified value, she can use the formula A > (wh)+ 0.5(bh). Rewrite this formula to solve for b. Show all steps in your work.

A > (wh)+0.5(bh) A(wh) > 0.5(bh) A(wh) * 2 > (bh) A(wh) * 2/h > (b) This the answer I got, but I have a feeling it's not correct.

3. Nnesha

wh is adding with .5(bh) so to cancel out wh from right you need to do opposite of addition

4. Nnesha

multiplication <----opposite ----> division

5. Nnesha

??

Ok, so A - (wh) > 0.5(bh)

What I really need to know is how I deal with the 0.5. That's what's getting and it's on multiple problems

@Nnesha You there?

9. Nnesha

oops oh yea so that's right now multiply both sides by 2 remember .5 =1/2 so you can change it to fraction $\huge\rm A-wh>\frac{ bh }{ 2 }$

So the answer would be $b < A - (wh) * 2 \div h$

11. Nnesha

multiply left side by 2 so 2(a-wh)

12. Nnesha

$\huge\rm \frac{ 2(A-wh) }{ h }>b$ multiply whole thingy not just wh

13. Nnesha

now distribute parentheses by 2

Ah ok. Thank you so much!! I understand now.

15. Nnesha

my pleasure