cookie_monster
  • cookie_monster
HELP PLEASE!!! LITERAL EQUATIONS!!
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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schrodinger
  • schrodinger
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cookie_monster
  • cookie_monster
The area of this figure can be found by the formula A = (wh) + 0.5(bh). If Marcie wants the total area to be larger than a specified value, she can use the formula A > (wh)+ 0.5(bh). Rewrite this formula to solve for b. Show all steps in your work.
cookie_monster
  • cookie_monster
A > (wh)+0.5(bh) A(wh) > 0.5(bh) A(wh) * 2 > (bh) A(wh) * 2/h > (b) This the answer I got, but I have a feeling it's not correct.
Nnesha
  • Nnesha
wh is adding with .5(bh) so to cancel out wh from right you need to do opposite of addition

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Nnesha
  • Nnesha
multiplication <----opposite ----> division
Nnesha
  • Nnesha
??
cookie_monster
  • cookie_monster
Ok, so A - (wh) > 0.5(bh)
cookie_monster
  • cookie_monster
What I really need to know is how I deal with the 0.5. That's what's getting and it's on multiple problems
cookie_monster
  • cookie_monster
@Nnesha You there?
Nnesha
  • Nnesha
oops oh yea so that's right now multiply both sides by 2 remember .5 =1/2 so you can change it to fraction \[\huge\rm A-wh>\frac{ bh }{ 2 }\]
cookie_monster
  • cookie_monster
So the answer would be \[b < A - (wh) * 2 \div h\]
Nnesha
  • Nnesha
multiply left side by 2 so 2(a-wh)
Nnesha
  • Nnesha
\[\huge\rm \frac{ 2(A-wh) }{ h }>b\] multiply whole thingy not just wh
Nnesha
  • Nnesha
now distribute parentheses by 2
cookie_monster
  • cookie_monster
Ah ok. Thank you so much!! I understand now.
Nnesha
  • Nnesha
my pleasure

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