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anonymous
 one year ago
Find the x intercepts of the parabola with vertex (1,17) and y intercept (0,16)
anonymous
 one year ago
Find the x intercepts of the parabola with vertex (1,17) and y intercept (0,16)

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anonymous
 one year ago
Best ResponseYou've already chosen the best response.0please help me I will fan and medal

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0http://www.mathwarehouse.com/geometry/pa... Vertex Form of Equation y= a(xh)^2 + k Knowing (h,k) is the vertex, and the vertex is (1,17) y = (x1)^2  17 y = x^2  2x + 1  17 y = x^2  2x  16 Knowing: y = ax 2 + bx + c a = 1 b = 2 c = 16 Solving for x intercepts: http://www.analyzemath.com/quadratics/ve... x1 = [  b + sqrt (b^2  4 a c) ] / 2 a x2 = [  b  sqrt (b^2  4 a c) ] / 2 a Solving: x1 = [2 + sqrt(4 + 64)] / 2 x1 = (2 + sqrt(68)) / 2 x2 = [  b  sqrt (b^2  4 a c) ] / 2 a x2 = [2  sqrt(4 + 64)] / 2 x2 = (2  sqrt(68)) / 2 Therefore, rounding to the nearest hundredth: We know y is zero because they are xintercepts. (5.12, 0), (3.12, 0)

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0so all of that is rounded to the nearest hundredth?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0sorry it took so long to reply I had to take my dogs out :p

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0that's okay :) can you help me do the same thing with vertex 1,16 and y intercept 0,15?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Okay: first, write the equation of the parabola in the required form: (y  k) = a·(x  h)² Here, (h, k) is given as (1, 16). So you have: (y + 16) = a · (x + 1)² Unfortunately, a is not given. However, you do know one additional point on the parabola: (0, 15): 15 + 16 = a· (0 + 1)² .·. a = 1 .·. the equation of the parabola in vertex form is y + 16 = (x + 1)² The xintercepts are the values of x that make y = 0. So, let y = 0: 0 + 16 = (x + 1)² 16 = (x + 1)² We are trying to solve for x, so take the square root of both sides  but be CAREFUL! ± 4 = x + 1 ...... remember both the positive and negative roots of 16...... Solving for x: x = 1 + 4, x = 1  4 x = 3, x = 5. Or, if you prefer, (3, 0), (5, 0).

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Are you taking FLVS?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0These seem like the questions I had on my virtual school :p

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Yes I'm taking summer courses with Ed options Academy trough Plato

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Any more questions you need help with?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0vertex 1,245 and y intercept 0,240

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0y = a(x1)² + 245 240 = a+245 a = 5 y = 5(x1)² + 245 = 0 5(x²  2x + 1) + 245 = 0 x²  2x  48 = 0 (x8)(x+6) = 0 x = 6, 8 xintercepts: (6,0) and (8,0)

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Want me to explain that one more?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0no I think I got that one

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Alright :) (Thanks for the testimony)

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0no problem :) vertex (1,1) y intercept (0,3)

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0vertex form of equation for a parabola: y=A(xh)^2+k, (h,k)=coordinates of vertex solving for A: 3=A(01)^2+1 A=4 equation: y=4(x1)^2+1 xintercepts set y=0 4(x1)^2+1=0 (x1)^2=1/4 x1=±√(1/4)=±1/2 x=1±1/2 xintercepts: x=1/2 x=3/2

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0so how w\[(x _{1},y _{1}),(x _{2},y _{2})\]ould you write that as

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0for the one you just did

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0oh I think it would be (3/2,0) (0,3) To show the xintercept and the yintercept.

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0okay thank you that was my last one

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0No problem! Good Luck with your schooling!
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