Solve the system of equations. x + 3y = −1 2x + 2y = 6 (−4, 1) (2, −1) (4, −1) (5, −2)

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Solve the system of equations. x + 3y = −1 2x + 2y = 6 (−4, 1) (2, −1) (4, −1) (5, −2)

Mathematics
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At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.

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@Michele_Laino can u help me
Do you have a preferred method, substitution, addition, etc.?
Use the substitution method and isolate x in the first equation. x + 3y = -1 x + 3y - 3y = -1 - 3y x = -1 - 3y After you've isolated x, plug in what x equals onto the second equation. 2x + 2y = 6 2(-1 - 3y) + 2y = 6 Distribute the expression in parenthesis. Next, combine all like terms and solve for y. If you've received y, just plug it back in the first original equation to receive the value of x. That will be your (x, y) value, or your solution.

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Type both equations in this link. It will show you the steps. http://www.mathpapa.com/calc.html?q=x+y%3D7%2C%20x+2y%3D11

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